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masya89 [10]
3 years ago
15

What horizontally-applied force will accelerate a crate of mass 400 kg at 1 meter per second per second across a factory floor a

gainst a friction force of half its weight?
Physics
1 answer:
son4ous [18]3 years ago
6 0

Answer:

The horizontally applied force = 2360 N

Explanation:

<em>Force:</em> Force can be defined as the product of mass and acceleration. the S.I unit of force is Newton (N)

Fh = Fr + ma......... Equation 1

Where Fh = horizontally applied force, Fr = friction force, m = mass of the crate, a = acceleration of the crate.

<em>Given: m = 400 kg, a = 1 m/s²</em>

Fr = 1/2 W, W = mg  ⇒W = 400×9.8 = 3920 N

∴Fr = 1/2(3920), Fr = 1960 N

Substituting these values into equation 1

Fh = 1960 + 400×1

Fh = 1960 + 400

Fh = 2360 N

Therefore the horizontally applied force = 2360 N

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The speed of the ball moving is

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what is momentum?

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h = 6.626 \times 10 {}^{ - 34}kgm {}^{2}/s(plancks \: constant)

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p \: photons =  \frac{6.626 \times 10 {}^{ - 34}kgm {}  ^{2}/s }{700 \times 10 {}^{ - 9}m  }

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since,the Photon and the ping-pong ball have the same momentum,we have

pball = pphotons =  \frac{6.626 \times 10 {}^{ - 34}kgm/s  }{700 \times 10 {}^{ - 9} }

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learn more about momentum of photon from here: brainly.com/question/28197406

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A horizontal wire is hung from the ceiling of a room by two massless strings. The wire has a length of 0.11 m and a mass of 0.01
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Answer:

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