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Ne4ueva [31]
3 years ago
8

You are given two same party balloons (one filled with helium and the

Physics
1 answer:
alexgriva [62]3 years ago
6 0

Answer:

you have to substitute the volume of the ballonn with no ruler

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Two resistors of 12Ω and 2Ω are connected in parallel to a battery of 4 V. Current through 12Ω resistor will be _____________ an
Alex

Answer:

0.33  Amp

8 Watts

Explanation:

The current through the 12 Ω resistor will be given by Ohm's law:

4 V / 12 Ω = 1/3 Amp ≈ 0.33  Amp

The power dissipated on the 2 Ω resistor can be calculated via the formula: \frac{V^2}{R}  which gives:

4^2 / 2 = 8 Watts

6 0
3 years ago
At a certain time a particle had a speed of 48 m/s in the positive x direction, and 4.5 s later its speed was 92 m/s in the oppo
larisa86 [58]

Answer:

-31.1 m/s^2

Explanation:

The acceleration of an object is the rate of change of velocity of the object.

Mathematically, it is calculated as:

a=\frac{v-u}{t}

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

Acceleration is a vector, so it is important to also take into account the direction of the velocity.

For the particle in this problem, we have:

u = +48 m/s is the initial velocity (positive direction)

v = -92 m/s is the final velocity (negative direction)

t = 4.5 s is the time interval

Therefore, the average acceleration is

a=\frac{v-u}{t}=\frac{-92-(+48)}{4.5}=-31.1 m/s^2

4 0
3 years ago
Energy input remains constant and voltage remains the same in a circuit, but current decreases. Which must be happening?
RUDIKE [14]
A) the resistance is increasing

Hope this helped!
6 0
4 years ago
1. Do you feel Doc's habits and routine have led to his success? Explain
AfilCa [17]
EA SPORTS its in the THE GAME
4 0
3 years ago
The​ half-life of a certain radioactive substance is 12 hours. There are 19 grams present initially. a. Express the amount of su
neonofarm [45]

Answer:

(a) N=19\times e^{-\lambda t}

(b) 15 hours

Explanation:

half life, T = 12 hours

No = 19 g

(a) Let N be the amount remaining after time t.

Let λ be the decay constant.

\lambda =\frac {0.6931}{T}

The equation of radioactivity used here is given by

N=N_{o}e^{-\lambda t}

N=19\times e^{-\lambda t}

(b) N = 8 gram

Substitute the values in above equation

\lambda =\frac {0.6931}{12}

λ = 0.0577 per hour

So, 8=19\times e^{-0.577t}

e^{-0.0577t}=0.421

Take natural log on both the sides

- 0.0577 t = - 0.865

t = 15 hours

4 0
3 years ago
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