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Brilliant_brown [7]
4 years ago
13

Pls pls help me 20 minutes left pls help

Chemistry
1 answer:
irakobra [83]4 years ago
3 0

Answer:

seed and spores

Explanation:

I wish I'm correct

hope this helps

If I'm wrong SORRY

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Which is a good example of a contact force?
Alex Ar [27]

D bc they actually contacted each other

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3 years ago
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The Moon is always half lit and half dark.
Natasha_Volkova [10]

Answer:

True

Explanation:

Just like the Earth, half of the Moon is lit by the Sun while the other half is in darkness.

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When we mix Cu wire with Silver Nitrate, the following reaction OCCURS.
kherson [118]

Answer:

Yes

2Ag + Cu(No3)2 -----(heat) ----- Cu + 2Agno3

When heat energy is passed through Cu(No3)2 then the reverse reaction will occur

3 0
3 years ago
Determine whether the graph is that of a function by using the vertical-line test. If it is, use the graph to find (a) its domai
Ilia_Sergeevich [38]

Answer:

Following are the solution to this question:

Explanation:

If the draw a line perpendicular with y-axis thru the diagonal line check but it meets only one curved point, therefore the curve indicates a function not otherwise.  They draw a vertical line perpendicular to the y-axis there, it just intersects one more chart point, which is why a graph is a feature:

In point a:

\to Domain= [-\pi ,\pi ]\\\\\to Range = [-1,1]

In point b:

Its y-axis length cut also by understanding the benefits of y-interception and the x-axis length gives the x-intercept.  

\to y-intercept = 1\\\\\to x-intercept = \frac{\pi}{2} ,- \frac{\pi}{2} \\\\

In point C:

Every graph is y-axis symmetric because the left side of the column as well as the middle side of the graph is about the same.

3 0
3 years ago
A BaSO4 slurry is ingested before the gastrointestinal tract is x-rayed because it is opaque to x-rays and defines the contours
NNADVOKAT [17]

Explanation:

The given reaction equation is as follows.

         BaSO_{4}(s) \rightleftharpoons Ba^{2+}(aq) + SO_{4}^{2-}(aq)

The value of \Delta G^{o} = 59.1 kJ/mol

We know that ,

            \Delta G^{o} = -RT ln K_{sp}

 or,       ln K_{sp} = -(\frac{\Delta G^{o}}{RT})


                       = -(\frac{59.1 kJ/mol}{(8.314 \times 10^{-3} kJ/mol.K \times 310 K))}[/tex]  

            = -22.93

or,      K_{sp} = e^{-22.93}

                      = 1.1 \times 10^{-10}

      K_{sp} = [Ba^{2+}][ SO_{4}^{2-}]

Therefore,      [Ba^{2+}] =\sqrt{K_{sp}}

                                        = \sqrt{ 1.1 \times 10^{-10}}

                                         = 1.05 \times 10^{-5} M

Therefore, we can conclude that the value of [Ba^{2+}] in the intestinal tract is 1.05 \times 10^{-5} M.

7 0
3 years ago
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