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evablogger [386]

3 years ago

13

Make the following conversion. 60 dkm = _____ km

2 answers:

Harman [31]3 years ago

8 0

Answer: 0.60

Explanation:

Fudgin [204]3 years ago

5 0

60 dekameters is equal to 0.6 kilometers (km).
(There is no measurement abbreviated 'dkm')

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Stopping on snow and ice may require up to _____ the distance than normal conditions.

FromTheMoon [43]

Stopping on snow and ice may require up to ten times the distance than normal conditions.

In normal conditions you can drive easily, but when there is snow, ice, fog, rain, it is difficult to drive. Some people thought a stopping distance was twice as in normal condition but it can increase up to ten times in snow and ice.

4 0

3 years ago

Mario, a hockey player, is skating due south at a speed of 4.79 m/s relative to the ice. A teammate passes the puck to him. The

frez [133]

Mario's velocity vector relative to the ice is

$\vec v_{M/I}=-4.79\,\vec\jmath$

(note that all velocities mentioned here are given in m/s)

The puck is moving in a direction of 17.8 degrees west of south, or 252.2 degrees counterclockwise relative to east. Its velocity vector relative to the ice is then

$\vec v_{P/I}=9.13(\cos252.2^\circ\,\vec\imath+\sin252.2^\circ\,\vec\jmath)=-2.79\,\vec\imath-8.69\,\vec\jmath$

The velocity of the puch relative to Mario is

$\vec v_{P/M}=\vec v_{P/I}+\vec v_{I/M}=\vec v_{P/I}-\vec v_{M/I}$

$\vec v_{P/M}=-2.79\,\vec\imath-3.90\,\vec\jmath$

Then, relative to Mario,

a. the puck is traveling at a speed of $\boxed{\|\vec v_{P/M}\|=4.80}$ , and

b. is moving in a direction $\theta$ such that

$\tan\theta=\dfrac{-3.90}{4.80}\implies\theta=-126^\circ$

which is about $\boxed{35.6^\circ}$ west of south.

5 0

3 years ago

A Martian leaves Mars in a spaceship that is heading to Venus. On the way, the spaceship passes earth with a speed v = 0.80c rel

hjlf

To find the relative distance from one point to another it is necessary to apply the Relativity equations.

Under the concept of relativity the distance measured from a spatial object is given by the equation

$l = l_0 \sqrt{1-\frac{v^2}{c^2}}$

Where

$l_0$ = Relative length

v = Velocity of the spaceship

c = Speed of light

Replacing with our values we have that

$l = l_0 \sqrt{1-\frac{v^2}{c^2}}$

$l = 1.2*10^{11} \sqrt{1-\frac{0.8c^2}{c^2}}$

$l = 1.2*10^{11} \sqrt{1-0.8^2}$

$l = 7.2*10^{10}m$

Therefore the distance between Mars and Venus measured by the Martin is $7.2*10^{10}m$

8 0

3 years ago

A book that has a mass of 0.5 grams is pushed across a table with a force of 20 newtons what is the acceleration of the book? A.

Valentin [98]

Answer:

Explanation:

To solve this equation ,we need to apply Newton's second law. Which defines

Force = Mass* Acceleration

Mass = 0.5 g = 0.5*10^-3 Kg

Force = 20 N

Acceleration = Force / Mass

Acceleration = 20 N /0.5*10^-3 Kg

Acceleration = 40000 m/s^2

I believe you meant a mass of 0.5 Kg

In that case, the acceleration would be

Acceleration = 40 m/s^2

Option C

8 0

3 years ago

Read 2 more answers

Kinetic energy is a measure of the motion of ___. A.Materials b.particles c.solids

Ber [7]

The answer to your question is b. Particles

8 0

4 years ago