Answer:
22Ω
Explanation:
Given parameters:
Potential difference = 3.3V
Current = 0.15A
Unknown:
Resistance = ?
Solution:
According to ohm's law, potential difference, current and resistance are related by the expression below;
V = I R
where V is the voltage
I is the current
R is the resistance
3.3 = 0.15 x R
R =
= 22Ω
Answer: Alpha radiation
Explanation: Alpha decay : When a larger radioactive nuclei decays into smaller nuclei by releasing alpha radiation, the mass number and atomic number is reduced by 4 and 2 units respectively.

Beta decay : When a larger radioactive nuclei decays into smaller nuclei by releasing beta radiation, the atomic number is increased by 1 unit.

Gamma decay : When a larger radioactive nuclei decays into smaller nuclei by releasing gamma radiation, the mass number remains same.

Answer: The standard potential for this cell is +1.49 V at 25C.
Explanation:
![E^0_{[Sn^{2+}/Sn]}=-0.14V](https://tex.z-dn.net/?f=E%5E0_%7B%5BSn%5E%7B2%2B%7D%2FSn%5D%7D%3D-0.14V)
![E^0_{[Ti^{2+}/Ti]}=-1.63V](https://tex.z-dn.net/?f=E%5E0_%7B%5BTi%5E%7B2%2B%7D%2FTi%5D%7D%3D-1.63V)
As titanium has lower reduction potential, it will act as anode and tin will acts as cathode.

Using Nernst equation :
![E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Ti^{2+}]}{[Sn^{2+}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B2.303RT%7D%7BnF%7D%5Clog%20%5Cfrac%7B%5BTi%5E%7B2%2B%7D%5D%7D%7B%5BSn%5E%7B2%2B%7D%5D%7D)
where,
F = Faraday constant = 96500 C
R = gas constant = 8.314 J/mol.K
T = room temperature = 
n = number of electrons in oxidation-reduction reaction = 2

Where both
are standard reduction potentials.
= standard electrode potential of the cell = 1.49 V
= emf of the cell = ?
Now put all the given values in the above equation, we get:


Answer:
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Explanation:
<h2>
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