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3 years ago

Balance the equation below. _NH4OH + __H3PO4 =>_(NH4)3PO4 + _H2O

Chemistry

1 answer:

larisa [96]3 years ago

8 0

Answer:

Double Displacement (Metathesis)

Explanation:a chemical reaction between two compounds in which parts of each are interchanged to form two new compounds (AB+CD=AD+CB)

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When 1.14 g of octane (molar mass = 114 g/mol) reacts with excess oxygen in a constant volume calorimeter, the temperature of th

maxonik [38]

I can't answer this question without knowing what the specific heat capacity of the calorimeter is. Luckily, I found a similar problem from another website which is shown in the attached picture.

Q = nCpΔT
Q = (1.14 g)(1 mol/114 g)(6.97 kJ/kmol·°C)(10°C)(1000 mol/1 kmol)
Q = +6970 kJ

8 0

3 years ago

Using spectroscopic notation write the complete electron configuration for the fluorine atom. Using noble gas notation write the

prohojiy [21]

Explanation:

Flourine has atomic number of 9 and hence 9 electrons in its neutral state. The full electronic configuration is given as;

1s2 2s2 2p5

Carbon has atomic number of 6 and hence 6 electrons in it's neutral state. The noble gas notation as the following format;

[closest noble gas before the element] remaining electrons

The nearest noble gas to carbon is Helium, the noble gas notation is given as;

[He] 2s4

3 0

3 years ago

7th grade Sem 1

Murrr4er [49]

Answer: Water

Explanation: During photosynthesis, plants take in carbon dioxide (CO2) and water (H2O) from the air and soil

4 0

3 years ago

Read 2 more answers

Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

anygoal [31]

Answer : The enthalpy of the given reaction will be, -1048.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The main reaction is:

$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$