Which calculation is an example of velocity ? 10m/s 10/Ms to the right 10 m to the right 10
1 answer:
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Answer:
See bolded below.
Explanation:
Consider the " Before " and " After. " " Before, " this particle 1 was trying to catch up with this particle 2, and " after " particle one had collided with particle two. Take a look at the attachment below for a more detailed examination.
Here is how this will play out. Particle 1, with great velocity, will hit particle 2, which would mean that Particle 2 has less velocity than Particle 1. Now after the collision, energy is transferred to Particle 2, and while Particle 1 has now stopped in it's tracks, Particle 2 - with more energy than before - will continue as long as it has to before friction eventually brings it to a stop.
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From this we can conclude that Vf, from the picture below, must have less energy than V1, but more energy than V2 - and vice versa.
Answer:
Part A:
Part B:
Explanation:
Part A:
Formula of Electric Field Strength:
Where:
x is the distance from the ring
R is the radius of the ring
is constant permittivity of free space=8.854*10^-12 farads/meter
Q is the charge
For right Ring E at the midpoint can be calculated as:
x for right plate=25/2=12.5 cm=0.125 m
Radius=R=10/2=5 cm=0.05 m
For Left Ring E at the midpoint can be calculated as:
Since charge on both plates is +ve and same in magnitude, the electric field will be same for both plates.
Electric Field at midpoint:
Both rings have same magnitude but the direction of fields will be opposite as they have same charge on them.
Part B:
At center of left ring:
Due to left ring Electric field at center is zero because x=0.
Due to right ring Electric field at center of left ring:
Now: x=25 cm= o.25 m (To the center of left ring)
Electric Field Strength at center of left ring is same as that of right ring.