Answer:
Explanation:
2 mole x 6.023x 10^23atoms/mole =12.04 atoms
To solve this we need to have knowledge of differential rate law which relate the rate to the concentration and time. Therefore, the rate of overall reaction is 1x10⁻²M/s.
<h3>
What is differential rate law? </h3>
A differential rate law represents the rate of a reaction . According to this rate is directly proportional to changes in the concentration of reactants and inversely proportional to specific interval of time. There is another expression of rate law which is integrated rate law which is just opposite of differential rate law.
The given equation is
2NO + O 2NO
(1/2) Rate of disappearance of NO= rate of disappearance of C= (1/2)rate of appearance of NO= rate of overall reaction.
(1/2)rate of appearance of NO= rate of overall reaction.
rate of appearance of NO=2x10⁻²M/s.
Substituting the values in above equation
(1/2)×2x10⁻²M/s = rate of overall reaction.
rate of overall reaction= 1x10⁻²M/s
Therefore, the rate of overall reaction is 1x10⁻²M/s.
To know more about differential rate law, here:
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Answer:
0.7g of HCl
Explanation:
First, let us write a balanced equation for the reaction between HCl and Al(OH)3.
This is illustrated below:
Al(OH)3 + 3HCl —> AlCl3 + 3H2O
Next, let us obtain the masses of Al(OH)3 and HCl that reacted together according to the equation. This can be achieved as shown below:
Molar Mass of Al(OH)3 = 27 + 3(16+1)
= 27 + 3(17) = 27 + 51 = 78g/mol.
Molar Mass of HCl = 1 + 35.5 = 36.5g/mol
Mass of HCl from the balanced equation = 3 x 36.5 = 109.5g
Now we can obtain the mass of HCl that would react with 0.5g of Al(OH)3. This can be achieved as follow:
Al(OH)3 + 3HCl —> AlCl3 + 3H2O
From the equation above,
78g of Al(OH)3 reacted with 109.5g of HCl.
Therefore, 0.5g of Al(OH)3 will react with = (0.5 x 109.5)/78 = 0.7g of HCl
What time tho?
you did not put when
According to
Graham's Law of Diffusion,"the rates of diffusion of two gases are inversely proportional to the square root of their Molar masses or Densities at the same pressure and temperature".
r₁ / r₂ =
Where,
r₁ = Rate of Helium
r₂ = Rate of Oxygen
M₂ = Molar mass of Oxygen = 32 g/mol
M₁ = Molar mass of Fluorine = 4 g/mol
Putting values,
r₁ / r₂ =
r₁ / r₂ =
r₁ / r₂ =
2.82
Result:
Helium gas effuses
2.82 times faster than Oxygen gas.