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fiasKO [112]
3 years ago
9

What volume of water would be added to 16.5 ml of a 0.0813 m solution of sodium borate in order to get a 0.0200 m s?

Chemistry
1 answer:
raketka [301]3 years ago
7 0
When diluting solutions from concentrated solutions the following formula can be used 
c1v1 = c2v2 
where c1 is concentration and v1 is volume of the concentrated solution 
and c2 is concentration and v2 is volume of the diluted solution to be prepared
substituting these values 
0.0813 M x 16.5 mL = 0.0200 M x V
V = 67.1 mL
the volume of the diluted solution prepared is 67.1 mL.
the volume of water that should be added to get a final volume of 67.1 mL is (67.1 - 16.5 ) = 50.6 mL
a volume fo 50.6 mL should be added 
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17.6kg

Explanation:

mass = Volume × Density

mass = 5000cm^3 × 3.52g/cm^3

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The pressure of a sample of helium in a 200. ml. container is 2.0 atm. If the 5 points
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The pressure of the gas = 40 atm

<h3>Further explanation</h3>

Given

200 ml container

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final volume = 10 ml

Required

Final pressure

Solution

Boyle's Law  

At a fixed temperature, the gas volume is inversely proportional to the pressure applied  

\tt \rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

Input the value :

P₂ = P₁V₁/V₂

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3 0
3 years ago
Identify the group number of following oxides/hydrides in Mendeleev
Ivan

Answer:

See explanation

Explanation:

The oxides or hydrides are formed by exchange of valency between the two atoms involved. The group of the atom bonded to oxygen or hydrogen in the binary compound can be deduced by considering the subscript attached to the oxygen or hydrogen atom.

Now let us take the journey;

R2O3- refers to an oxide of a group 13 element, eg Al2O3

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5 0
3 years ago
The average molecular speed in a sample of Ar gas at a certain temperature is 391 m/s. The average molecular speed in a sample o
adoni [48]

Answer:

550 m/s

Explanation:

The average molecular speed (v) is the speed associated with a group of molecules on average. We can calculate it using the following expression.

v = \sqrt{\frac{3 \times R \times T}{M} }

where,

  • R: ideal gas constant
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We can use the info of argon to calculate the temperature for both samples.

T = \frac{v^{2} \times M}{3 \times R} = \frac{(391m/s)^{2} \times 39.95g/mol}{3 \times 8.314J/k.mol} = 2.45 \times 10^{5} K

Now, we can use the same expression to find the average molecular speed in a sample of Ne gas.

v = \sqrt{\frac{3 \times R \times T}{M} } = \sqrt{\frac{3 \times (8.314J/k.mol) \times 2.45 \times  10^{5}K }{20.18g/mol} } = 550 m/s

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3 years ago
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