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Alexus [3.1K]
3 years ago
13

What is the weight of an object (mass = 60 kilograms) on Mars, where the acceleration due to gravity is 3.75 meters/second2?. Se

lect one of the options below as your answer:. A. 1.6 newtons. B. 16 newtons. C. 22.5 newtons. D. 225 newtons. E. 2250 newtons.
Physics
2 answers:
UNO [17]3 years ago
0 0
The weight (W) of an object is the product of its mass (m) and the acceleration (a). That is,
                                    W = m x a
Substituting the known values give,
                                W = (60 kg) x (3.75 m/s²) = 225 N
Thus, the object's weight is 225 N. The answer is letter D.
belka [17]3 years ago
0 0
Weight = mass * gravity = 60 kg * 3.75 m/s² = 225 N

Option D.
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Answer:

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The negative sign shows that ball down the ground or moving down

Explanation:

Vf² - Vo² = 2gS

where

Vf = velocity of clay as it hits the ground

Vo = initial velocity of clay = 0

g = acceleration due to gravity = 9.8 m/sec^2 (constant)

S = distance travelled by clay = 15 m

Substituting appropriate values,

Vf² - 0 = 2(9.8)(15)  

Vf = 17.15 m/sec.

Formula to use is,  

V - Vf = aT

where

V = velocity of clay when it stops = 0

Vf = 17.15 m/sec (as determined above)

a = acceleration

T = 20 ms  

Put the values to find acceleration

a=(V-Vf)/T

a=(0-17.15)/20

a= -0.86 m/s²

The negative sign shows that ball down the ground

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7 0
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alukav5142 [94]
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A certain spring stretches 3 cm when a load of 15 n is suspended from it. how much will the spring stretch if 30 n is suspended
Alik [6]
Initially, the spring stretches by 3 cm under a force of 15 N. From these data, we can find the value of the spring constant, given by Hook's law:
k= \frac{F}{\Delta x}
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Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring:
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4 0
3 years ago
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A ball with an initial velocity of 12 m/s is rolling up a hill. The ball accelerates at a rate of -2.6 m/s/s.
Anon25 [30]

Answer:

4.61 seconds

Explanation:

Given data

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From the given data

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time= velocity/acceleration

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