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Alexus [3.1K]
3 years ago
13

What is the weight of an object (mass = 60 kilograms) on Mars, where the acceleration due to gravity is 3.75 meters/second2?. Se

lect one of the options below as your answer:. A. 1.6 newtons. B. 16 newtons. C. 22.5 newtons. D. 225 newtons. E. 2250 newtons.
Physics
2 answers:
UNO [17]3 years ago
0 0
The weight (W) of an object is the product of its mass (m) and the acceleration (a). That is,
                                    W = m x a
Substituting the known values give,
                                W = (60 kg) x (3.75 m/s²) = 225 N
Thus, the object's weight is 225 N. The answer is letter D.
belka [17]3 years ago
0 0
Weight = mass * gravity = 60 kg * 3.75 m/s² = 225 N

Option D.
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Answer:

a) 10.51 J

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Explanation:

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m = slope  = ( Δ f / Δ x ) = 2.8 / -7.5 = - 0.373 N/m

x = distance travelled on the x axis by the train = 7.5 m

F = force experienced by the train = 2.8 N

x = 0

∴ b = 2.8

hence equation 1 can be written as

F = ( -0.373) x + 2.8   ----- ( 2 )

hence to determine the work done by the force

W   = \int\limits^7_0 { ( -0.373) x + 2.8  )} \, dx     Note:  the limits are actually 7.5 and 0

∴ W ( work done ) = -10.49 + 21 = 10.51 J

<u>b) calculate the speed of the train at the end of its journey</u>

we will apply the work energy theorem

W = 1/2 m*v^2  -  1/2 m*u^2

∴ V^2 = 2 / M ( W + 1/2 M*u^2 )  ( input values into equation )

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The Steamboat Geyser in Yellowstone National Park shoots water into the air at 48.0 m/s. How
qwelly [4]

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

Given;

initial velocity of the water, u = 48 m/s

at maximum height the final velocity will be zero, v = 0

the water is going upwards, i.e in the negative direction of gravity, g = -9.8 m/s².

The maximum height reached by the water is calculated as follows;

v² = u² + 2gh

where;

h is the maximum height reached by the water

0 = u² + 2gh

0 = (48)² + ( 2 x -9.8 x h)

0 = 2304 - 19.6h

19.6h = 2304

h = 2304 / 19.6

h = 117.55 m

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A single-slit diffraction pattern is formed by monochromatic electromagnetic radiation from a distant source passing through a s
tatiyna

Answer:

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b. I₀  9.36 x 10⁻⁵

Explanation:

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β = 56.0 rad , θ = 3.09 ° , γ = 0.170 mm = 0.170 x 10⁻³ m

a.

The wavelength of the radiation can be find using

β = 2 π / γ * sin θ

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b.

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I = I₀ (4 / β² ) * sin ( β / 2)²

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I = I₀  9.36 x 10⁻⁵

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