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Alexus [3.1K]
3 years ago
13

What is the weight of an object (mass = 60 kilograms) on Mars, where the acceleration due to gravity is 3.75 meters/second2?. Se

lect one of the options below as your answer:. A. 1.6 newtons. B. 16 newtons. C. 22.5 newtons. D. 225 newtons. E. 2250 newtons.
Physics
2 answers:
UNO [17]3 years ago
0 0
The weight (W) of an object is the product of its mass (m) and the acceleration (a). That is,
                                    W = m x a
Substituting the known values give,
                                W = (60 kg) x (3.75 m/s²) = 225 N
Thus, the object's weight is 225 N. The answer is letter D.
belka [17]3 years ago
0 0
Weight = mass * gravity = 60 kg * 3.75 m/s² = 225 N

Option D.
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Jill does twice as much work as Jack does and in half the time. Jill's power output is Group of answer choices one-fourth as muc
Musya8 [376]

Answer:

Second Choice.

Explanation:

Jack's Power = W/t

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Second Choice

3 0
2 years ago
A(n) 10.1 g bullet is fired into a(n) 2.41 kg ballistic pendulum and becomes embedded in it. The acceleration of gravity is 9.8
fomenos

Answer:

v = 186.90\,\frac{m}{s}

Explanation:

The motion of ballistic pendulum is modelled by the appropriate use of the Principle of Energy Conservation:

\frac{1}{2}\cdot (m_{p}+m_{b})\cdot v^{2} = (m_{p}+m_{b})\cdot g \cdot h

The final velocity of the system formed by the ballistic pendulum and the bullet is:

v = \sqrt{2\cdot g\cdot h}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (0.031\,m)}

v\approx 0.78\,\frac{m}{s}

Initial velocity of the bullet can be calculated from the expression derived of the Principle of Momentum:

(0.0101\,kg)\cdot v = (2.41\,kg + 0.0101\,kg)\cdot (0.78\,\frac{m}{s} )

v = 186.90\,\frac{m}{s}

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3 years ago
Which would have the longer orbital period: a moon 1 million km from the center of Jupiter, or a moon 1 million km from the cent
Harman [31]

Answer:

earth

Explanation:

The formula for the orbital period of the moon is given by

T = 2\pi \sqrt{\frac{r}{g}}

As the time period is inversely proportional to the square root of the acceleration due to gravity of the planet.

As the value of acceleration due to gravity on Jupiter is more than the earth, so the period of moon around the earth is large as compared to the period of the moon around the Jupiter when the distance is same.

5 0
3 years ago
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