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3 years ago

Anton created a chart listing different types of materials.

Physics

2 answers:

In-s [12.5K]3 years ago

6 0

Answer : The correct option is, (C)X: paper Y: silicon

Explanation :

Conductor : Conductors are those substance which have ability to pass electric current through them. Most of the metals are good conductors.

For example : copper, gold, silver, aluminium, etc.

Insulator : Insulators are those substance which do not have ability to pass electric current through them.

For example : wood, plastic, glass, paper, etc.

Semiconductor : Semiconductors are those substance which have ability to allow or suppress the electric current.

For example : carbon, silicon, germanium, etc.

Superconductor : Superconductor are those substance which conduct electricity with zero resistance.

For example : mercury, lead, etc.

Thus, 'X' will be paper and 'Y' will be silicon.

Shkiper50 [21]3 years ago

5 0

the answer is c paper is in fact an insulator

and silicon is a mettaloid which makes it a semi conductor

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3 years ago

Air contained in a rigid, insulated tank fitted with a paddle wheel, initially at 300 K, 2 bar, and a volume of 3 m3, is stirred

madam [21]

Answer:

a)P₂ =4 bar

b)W= - 1482.48 KJ

It means that work done on the system.

c)S₂ - S₁ = 3.42 KJ/K

Explanation:

Given that

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T₂ = 600 K ,V₂=V₁ 3 m³

Given that tank is rigid and insulated.It means that volume of the gas will remain constant.

Lets take the final pressure = P₂

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$P_2=\dfrac{T_2}{T_1}\times P_1$

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P₂ =4 bar

Internal energy

ΔU = m Cv ΔT

Cv=0.71 KJ/kg.k for air

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$m=\dfrac{200\times 3}{0.287\times 300}\ kg$

m= 6.96 kg

ΔU= 6.96 x 0.71 x (600 - 300)

ΔU=1482.48 KJ

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Q= ΔU + W

Q= 0 Insulated

W = - ΔU

W= - 1482.48 KJ

It means that work done on the system.

Change in the entropy

$S_2-S_1=mC_v\ \ln\dfrac{T_2}{T_1}$

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3 years ago

An incompressible fluid (water) is flowing through a pipe of diameter 20 cm with

sergey [27]

Answer:

115 kPa

Explanation:

Use Bernoulli equation:

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

Assuming no elevation change, h₁ = h₂.

P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²

Plugging in values:

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P = 115,000 Pa

P = 115 kPa

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3 years ago