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2 years ago

A private plane pilot is what kind of individual transportation position? professional level mid-level entry-level EPA-certified

Engineering

1 answer:

gayaneshka [121]2 years ago

3 0

Answer:

A private plane pilot is a mid-level position.

Explanation:

The six pilot certifications in the US are as follows:

Sport Pilot
Recreational Pilot
Private Plane Pilot
Commercial Plane Pilot
Flight Instructor
Airline Transport Pilot

From this listing, it is evident that the Private Plane Pilot is in the mid of the line so it is a mid-level position.

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A dc shunt motor rated at 240 V has a field winding resistance of 120 Ω and an armature resistance of 0.12 Ω. The motor is suppl

patriot [66]

Answer:

a) see attached pic

b) No-load speed: 1368 rpm

c) IL at 1% below no-load speed = 22.4 A

Explanation:

(See attached pic)

b) The No- Load Speed:

Since, Ea = KФn [ Ea=Internal Generated Voltage, k=Machine constant,Ф=flux, n=speed]

As the Vt (terminal voltage) and field resistance (Rf) is constant, If (field current is constant. Assuming negligible armature reaction, the following relationship can be written,

Ea2 / Ea1 = K Ф n2 / K Ф n1

Since K and flux is contant,

Ea2 = (n2 / n1) x Ea1

Or, n2 = (Ea2 / Ea1) x n1 -------- (1)

Since, Ea = Vt - IaRa

But at no load, Ia = 0, therefore,

Ea = Vt

At load condition, IL = 29 A

Therefore,

Ia = IL - Vt/Rf

Ia = 29 - 240/120

Ia = 27 A

Therefore, Ea at this load will be,

Ea = Vt - IaRa

Ea = 240 - (27)(0.12)

Ea = 236.76 V

The No-Load speed of motor can be calculated using equation (1),

n2 = (Ea2 /Ea1 ) x n1

1350 = (236.76/240) x n1

n1 = 1368 rpm = No-load Speed

Now, if the speed is 1% below the no-load speed, which is,

n1 = no load speed = 1368 rpm

n2 = 1% less speed = 1354 rpm [ 1368 - (0.01)(1368) ]

Using equation (1),

n2 = (Ea2/Ea1) x n1

1354 = (Ea2/240) x 1368

Ea2 = 237.5 V

Since, Ea = Vt - IaRa

Ia = (Vt - Ea)/ Ra

Ia = (240-237.5)/(0.12)

Ia = 20.4 A

Now,

IL = Ia + If

IL = 20.4 + 240/120

IL = 22.4 A

When, Speed = 1368 rpm, IL = 4.75 A

When , Speed = 1354 rpm, IL = 22.4 A

When, Speed = 1350 rpm., IL = 29 A

(See attached pic)

7 0

3 years ago

An aluminium alloy bar of diameter 12.5 mm and length 27 m loaded in uniaxial tension to a force of 3 kN. Determine the length o

KonstantinChe [14]

Answer:

27009.56 mm

Explanation:

Given:

Diameter of the aluminium alloy bar, d = 12.5 mm

Length of the bar, L = 27 m = 27 × 10³ mm

Tensile force, P = 3 KN = 3 × 10³ N

Elastic modulus of the bar, E = 69 GPa = 69 × 10³ N/mm²

Now,

for the uniaxial loading, the elongation or the change in length (δ) due to the applied load is given as:

$\delta=\frac{PL}{AE}$

where, A is the area of the cross-section

$A=\frac{\pi d^2}{4}$

$A=\frac{\pi\times12.5^2}{4}$

A = 122.718 mm²

on substituting the respective values in the formula, we get

$\delta=\frac{3\times10^3\times27\times10^3}{122.718\times69\times10^3}$

δ = 9.56 mm

Hence, the length after the force is applied = L + δ = 27000 + 9.56

= 27009.56 mm

7 0

2 years ago

Select the correct answer. Felix aspires to be an engineer working for the government. What credentials will Felix require to ap

Aneli [31]

Answer:

Explanation:

5 0

2 years ago

List the parts of a manual transmission List the parts of a typical clutch assembly?

True [87]

Answer:

Explanation: Clutch Plate.

Clutch Cover.

Clutch Bearing (Release bearing)

Release Fork (clutch fork)

7 0

2 years ago

If you are interested only in the temperature range of 20° to 40°C and the ADC has a 0 to 3V input range, design a signal condit

mario62 [17]

Explanation:

Temperature range → 0 to 80'c

respective voltage output → 0.2v to 0.5v

required temperature range 20'c to 40'c

Where T = 20'c respective voltage

$\begin{aligned}v_{20} &=0.2+\frac{0.5-0.8}{80} \times 20 \\&=0.2+\frac{0.3}{80} \times 20 \\V_{20} &=0.275 v\end{aligned}$

$\begin{aligned}\text { when } T=40^{\circ} C & \text { . } \\v_{40} &=0.2+\frac{0.5-0.2}{80} \times 40 \\&=0.35 V\end{aligned}$

Therefore, Sensor output changes from 0.275v to 0.35volts for the ADC the required i/p should cover the dynamic range of ADC (ie - 0v to 3v)

so we have to design a circuit which transfers input voltage 0.275volts - 0.35v to 0 - 3v

Therefore, the formula for the circuit will be

$\begin{array}{l}v_{0}=\left(v_{i n}-0.275\right) G \\\sigma=\ldots \frac{3-0}{0.35-0.275}=3 / 0.075=40 \\v_{0}=\left(v_{i n}-0.275\right) 40\end{array}$

The simplest circuit will be a op-amp

NOTE: Refer the figure attached

Vs is sensor output

Vr is the reference volt, Vr = 0.275v

$\begin{aligned}v_{0}=& v_{s}-v_{v}\left(1+\frac{R_{2}}{R_{1}}\right) \\\Rightarrow & \frac{1+\frac{R_{2}}{R_{1}}}{2}=40 \\& \frac{R_{2}}{R_{1}}=39 \quad \Rightarrow\end{aligned}$

choose R2, R1 such that it will maintain required ratio

The output Vo can be connected to voltage buffer if you required better isolation.

3 0

2 years ago