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Kaylis [27]
3 years ago
9

A private plane pilot is what kind of individual transportation position? professional level mid-level entry-level EPA-certified

Engineering
1 answer:
gayaneshka [121]3 years ago
3 0

Answer:

A private plane pilot is a mid-level position.

Explanation:

The six pilot certifications in the US are as follows:

  1. Sport Pilot
  2. Recreational Pilot
  3. Private Plane Pilot
  4. Commercial Plane Pilot
  5. Flight Instructor
  6. Airline Transport Pilot

From this listing, it is evident that the Private Plane Pilot is in the mid of the line so it is a mid-level position.

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GarryVolchara [31]

Answer: barries

Explanation:

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A safety interlock module operates by monitoring the voltage from the
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Answer: its an Ignition coil

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4 years ago
A 40 mph wind is blowing past your house and speeds up as it flows up and over the roof. If the elevation effects are negligible
Finger [1]

The pressure at the point on the roof where the speed is 60mph is 14.66 psi

<u>Explanation:</u>

The question follows Bernoulli's equation

P1 + 1/2 ρ V1² = P2 + 1/2 ρ V2²

V1 = 40 X 5280 / 3600 = 58.7 ft/s

V2 = 60 X 5280 / 3600 = 88 ft/s

P2 = P1 + 1/2 ( 0.00238 ) [(58.7)² - (88)²]

P2 - P1 = -5.12lb/ft²

The negative pressure created tends to lift the roof.

We know,

P1 = 14.7 psi = 2116.8 lb/ft²

P2 = 2116.8 - 5.12 lb/ft²

P2 = 2111.68 lb/ft²

P2 = 14.66 psi

Therefore, the pressure at the point on the roof where the speed is 60mph is 14.66 psi

7 0
3 years ago
A hollow steel cylinder with an outside diameter of 100 mm is required to carry a tensile load of 500 kN. Given that the allowab
ivolga24 [154]

Answer:

Maximum inside diameter is 68.52 mm.

Explanation:

Apply stress formula to calculate inside diameter of the tube. Take the allowable stress for safe design and maximum inside diameter of the steel tube.

Step1

Given:

Outside diameter is 100 mm.

Tensile load is 500 kN.

Allowable stress is 120 Mpa.

Calculation:

Step2

Inside diameter is calculated by the stress formula as follows:

\sigma_{a}=\frac{F}{A}

\sigma_{a}=\frac{F}{\frac{\pi}{4}(d_{o}^{2}-d_{i}^{2})}

120=\frac{500\times1000}{\frac{\pi}{4}(100^{2}-d_{i}^{2})}

(100^{2}-d_{i}^{2})=5305.164

d_{i}=68.52mm

Thus, the inner diameter is 68.52 mm.

6 0
3 years ago
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