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Triss [41]
2 years ago
9

The arterioles (small arteries) leading to an organ, constrict in order to decrease flow to the organ. To shut down an organ, bl

ood flow is reduced naturally to 1.00% of its original value. By what factor did the radii of the arterioles constrict?
Physics
1 answer:
Alinara [238K]2 years ago
3 0

Answer:

x=0.01^{1/4}

Explanation:

As the flow rate Q is given as:

Q=\frac{(p_{2}-p_{1} )\pi r^{4} }{8nl}

In case of all other parameters are constant.We could write it as:

Q=constant*r^{4}

Reducing  Q to 1% we could write it as:

0.01Q=constant*(r^{4} )\\

Where x is factor or r  to reduce Q to 1%.From this we got

0.01=x^{4}\\ So\\x=0.01^{1/4}

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A bicyclist of mass 90 kg drives around a circle with a centripetal acceleration
Serggg [28]

given,

mass of bicyclist(m)=90Kg

centripetal acceleration(a)=1.5 m/s2

centripetal force(F)=ma= 90×1.5=145 N

5 0
3 years ago
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Which is an example of reflection
Elena-2011 [213]

Common examples include the reflection of light, sound and water waves. The law of reflection says that for specular reflection the angle at which the wave is incident on the surface equals the angle at which it is reflected. Mirrors exhibit specular reflection.

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2 years ago
Block B is attached to a massless string of length L = 1 m and is free to rotate as a pendulum. The speed of block A after the c
Amanda [17]

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The minimum velocity of A is  v_A= 4m/s

Explanation:

From the question we are told that

    The length of the string is  L = 1m

     The initial speed of block A is u_A

     The final speed of block A is  v_A = \frac{1}{2}u_A

      The initial speed of block B is u_B = 0

      The mass of block A  is  m_A = 7kg  gh

      The mass of block B is  m_B  = 2 kg

According to the principle of conservation of momentum

       m_A u_A + m_B u_B = m_Bv_B + m_A \frac{u_A}{2}

Since block B at initial is at rest

       m_A u_A  = m_Bv_B + m_A \frac{u_A}{2}

      m_A u_A  - m_A \frac{u_A}{2} = m_Bv_B

          m_A \frac{u_A}{2} = m_Bv_B

  making v_B the subject of the formula

             v_B =m_A \frac{u_A}{2 m_B}

Substituting values

               v_B =\frac{7 u_A}{4}  

This v__B is the velocity at bottom of the vertical circle just at the collision with mass A

Assuming that block B is swing through the vertical circle(shown on the second uploaded image ) with an angular velocity  of v__B' at  the top of the vertical circle  

 The angular centripetal acceleration  would be mathematically represented

                   a= \frac{v^2_{B}'}{L}

Note that  this acceleration would be toward the center of the circle

      Now the forces acting at the top of the circle can be represented mathematically as

         T + mg = m \frac{v^2_{B}'}{L}

    Where T is the tension on the string

  According to the law of energy conservation

The energy at  bottom of the vertical circle   =  The energy at the top of

                                                                                the vertical circle

   This can be mathematically represented as

                 \frac{1}{2} m(v_B)^2 = \frac{1}{2} mv^2_B' + mg 2L

From above  

                (T + mg) L = m v^2_{B}'

Substitute this into above equation

             \frac{1}{2} m(\frac{7 v_A}{4} )^2 = \frac{1}{2} (T + mg) L  + mg 2L  

             \frac{49 mv_A^2}{16}  = \frac{1}{2} (T + mg) L + mg 2L

          \frac{49 mv_A^2}{16}  = T + 5mgL

The  value of velocity of block A needed to cause B be to swing through a complete vertical circle is would be minimum when tension on the string due to the weight of B is  zero

        This is mathematically represented as

                      \frac{49 mv_A^2}{16}  = 5mgL

making  v_A the subject

            v_A = \sqrt{\frac{80mgL}{49m} }

substituting values

          v_A = \sqrt{\frac{80* 9.8 *1}{49} }

              v_A= 4m/s

     

6 0
2 years ago
The circuit below contains an ideal battery, four identical light bulbs, and a switch. The switch is initially open.
Dafna1 [17]

The question is incomplete! circuit figure is attached below and answer and explanation is provided below.

Answer:

Bulb_A = Bulb_B = Bulb_D and Bulb_C = 0.

Explanation:

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When the switch is open Bulb_C is open circuited meaning that there is no way for the current to flow through it. This path offers infinite resistance to the current therefore, current will try to take a least resistance path that is through Bulb_B.

So eventually, when the switch is open the circuit becomes a simple series circuit with path From battery to Bulb_A to Bulb_B to Bulb_D to battery with Bulb_C = 0.

What happens in a series circuit?

We know that in a series circuit, there is only one path for the current to flow therefore, same current will flow through all the series Bulbs and their brightness will be same. Bulb_A = Bulb_B = Bulb_D

Brightness in a series circuit:

We also know know that in a series circuit, resistance gets summed up and voltage across each Bulb gets shared which results in less power dissipation that's why Bulbs connected in series appear dimmer as compared to when they are connected in parallel.

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2 years ago
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geniusboy [140]

Answer:The loudest of the two sound wave is second one

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2 years ago
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