………………………… what's the question
The formuka to calculate energy of photon is
E=hc/ Lambda
where h is planks constant
c is velocity of light in vaccume
lamda is the wavelength.
Now
h= 6.626×10^-34 J s
c= 3×10^8 m/s
lamda=350 nanometers= 350×10^-9 m
hence
E=(6.626×10^-34×3×10^8)/(350×+0^-9)
=(19.878×10^-26)/(350×10^-9)
=0.567×10^-17
=5.67×10^-16 J
The
balanced reaction would be written as:
<span>
C7H6O3 + C4H6O3--->C9H8O4 + HC2H3O2
To determine the percent yield, we need to first
determine the theoretical yield if the reaction were to proceed completely.
Then, we divide the actual yield that is given to the theoretical yield times
100 percent. The limiting reactant from the reaction would be salicylic acid.
We do as follows:
<span>Theoretical yield: 50.05 g C7H6O3 ( 1 mol /
138.21 g ) ( 1 mol C9H8O4 / 1 mol C7H6O3 ) ( 180.157 g / mol ) = 65.24 g C9H8O4 should be produced
Percent yield = 55.45 / 65.24 x 100 = 84.99%
<span>
Therefore, the percent yield for the given amount of salicylic acid is 84.99%
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The formula of the product when Br2 reacts with 3L of F2 to completion and produce 2 L of the product is
2 BrF3
Br2 +3F2 = 2BrF3
1 mole of Br reacted 3 moles of f2 to form 2 moles of BrF3
the formula we is as follows:-
M1V1= M2V2
where
M1=1.2
V1=0.133l
V2=41l
M2=?
1.2 × 0.133 = 41 × M2
0.1596 = 41 × M2
M2 = 0.15960/41
M2 = 0.0038926829