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Pepsi [2]
4 years ago
13

At the school book fair, Micah selected a

Mathematics
1 answer:
Anni [7]4 years ago
8 0

Answer:

$5.79 +

$0.95

Estamate

$5.80 +

$1.00

= $6.80

We only round one digit.

Step-by-step explanation:

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I need help to these questions. Convert these fractions to a decimal 7/8 , 4 3/8. Thanks
ehidna [41]
Simple...

you have: \frac{7}{8} and 4 \frac{3}{8}

Now, the first one is easy just divide it...

\frac{7}{8} =0.875

Now....

4 \frac{3}{8}    needs to be converted...

Multiply the whole number*denominator...

4*8=32

Now add the numerator....

32+3=35

Now use the original denominator...

\frac{35}{8}

Now divide...

\frac{35}{8}=4.375


Thus, your answer.
7 0
3 years ago
Read 2 more answers
In the last 6 years the population of Manchester, England, has grown at a rate of 0.8% per year to 530,300. If this rate continu
Rzqust [24]

Given parameters:

Current population  = 530,300 people

Growth rate  = 0.8% per year

Unknown

Population in 15 more years  = ?

To solve this problem, we  must compound the increase per year.

This implies that we treat the problem like that of a compound interest.

Since we know that population increases by 0.8%,

                          it is similar to 1 + \frac{0.8}{100}  = 1.008 increase

Now the population in 15years will be;

                530300 x (1.008)¹⁵  = 597626 people

So, the population after 15yrs is 597626 people

8 0
4 years ago
How do I find the symmetry
Novay_Z [31]
Symmetry is the same as the one side of the graph but it is fliped on the X-axis
3 0
3 years ago
Read this E[2X^2 â€" Y].
djyliett [7]

Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2<em>X </em>² - <em>Y</em>.

If you don't know how <em>X</em> or <em>Y</em> are distributed, but you know E[<em>X</em> ²] and E[<em>Y</em>], then it's as simple as distributing the expectation over the sum:

E[2<em>X </em>² - <em>Y</em>] = 2 E[<em>X </em>²] - E[<em>Y</em>]

Or, if you're given the expectation and variance of <em>X</em>, you have

Var[<em>X</em>] = E[<em>X</em> ²] - E[<em>X</em>]²

→   E[2<em>X </em>² - <em>Y</em>] = 2 (Var[<em>X</em>] + E[<em>X</em>]²) - E[<em>Y</em>]

Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.

6 0
3 years ago
What is the diameter?
Usimov [2.4K]

Answer:

13

Step-by-step explanation:

7 0
3 years ago
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