Question

Two point charges, +3.21 µC and -6.75 µC, are separated by 1.13 m. What is the electric potential midway between them?

Answer 1

Answer: The electric potential midway between them is -5.64 × 10^4 V

Explanation:

Electric potential is measured in volts or joules per coulomb. It is the amount of work required to move a charge from a reference point to a specific point inside the field.

Electric potential V = Σkq/r

k = coulomb's constant = 9.0x10^9 N-m^2/C^2

q1 = +3.21 × 10^-6 C

q2 = -6.75 × 10^-6 C

r = 1.13/2 = 0.565m

V = kq1/r + kq2/r = (k/r)(q1 + q2)

Substituting the values;

V = (9.0x10^9/0.565)(3.21 - 6.75) × 10^-6

V = -56389.3805309 Volt

V = -5.64 × 10^4 volts