1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tekilochka [14]
3 years ago
11

After observing the electric field in your trials above, where was the electric field the strongest? what was the direction of t

he electric field?
Physics
1 answer:
earnstyle [38]3 years ago
8 0
<span>Answer: Answer is The direction of the electric field is always directed in the direction that a positive test charge would be pushed or pulled if placed in the space surrounding the source charge.</span>
You might be interested in
Which of the following best describes how heat is transferred by conduction?
Verizon [17]

a. Particles in warmer objects make particles in colder objects move faster.

7 0
3 years ago
21
maks197457 [2]
An electrons transferred and compound forms
8 0
3 years ago
Read 2 more answers
Fill out the blanks, this is for science!
dusya [7]
Faster and higher I believe.
8 0
3 years ago
Read 2 more answers
What's the minimum Out PUT WORK<br> required to raise 14,0m3 of water 26.0m?
BartSMP [9]

Answer:

3.57 MJ

Explanation:

ASSUMING it's fresh water with density of 1000 kg/m³

W = ΔPE = mgΔh = 14.0(1000)(9.81)(26.0) = 3,570,840 J

Salt water would require more.

3 0
3 years ago
011 10.0 points
Ulleksa [173]

Answer:

2.47 m

Explanation:

Let's calculate first the time it takes for the ball to cover the horizontal distance that separates the starting point from the crossbar of d = 52 m.

The horizontal velocity of the ball is constant:

v_x = v cos \theta = (25)(cos 35.9^{\circ})=20.3 m/s

and the time taken to cover the horizontal distance d is

t=\frac{d}{v_x}=\frac{52}{20.3}=2.56 s

So this is the time the ball takes to reach the horizontal position of the crossbar.

The vertical position of the ball at time t is given by

y=u_y t - \frac{1}{2}gt^2

where

u_y = v sin \theta =(25)(sin 35.9^{\circ})=14.7 m/s is the initial vertical velocity

g = 9.8 m/s^2 is the acceleration of gravity

And substituting t = 2.56 s, we find the vertical position of the ball when it is above the crossbar:

y=(14.7)(2.56) - \frac{1}{2}(9.8)(2.56)^2=5.52 m

The height of the crossbar is h = 3.05 m, so the ball passes

h' = 5.52- 3.05 = 2.47 m

above the crossbar.

8 0
3 years ago
Other questions:
  • 1. what are valence electrons?
    11·2 answers
  • Big Bee has a mass of 5 kg and hits a newly cleaned windshield accelerating at a rate of 2 m/s2.
    7·1 answer
  • What is the complete back-and-forth motion of an object called?
    15·1 answer
  • You connect three resistors with resistances R, 2R, and 3R in parallel. The equivalent resistance of the three resistors will ha
    9·1 answer
  • Which process is used to make low cost energy by nuclear power plant​
    13·1 answer
  • Object B has a mass of 8 kg and was lifted at a rate of 3 m/s. What is the kinetic energy of object B?
    5·1 answer
  • HELP ASAP
    14·1 answer
  • A 250-kg moose stands in the middle of the railroad tracks in Sweden, frozen by the lights of an oncoming 10,000kg train traveli
    11·1 answer
  • Please help!!!!!!!!
    15·1 answer
  • When an object is placed 30.0 cm in front of a concave mirror, a real image is formed 60.0 cm
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!