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3 years ago

1. Which type of metal did Rutherford shoot alpha particles into?

1 answer:

7 0

<span>1. Which type of metal did Rutherford shoot alpha particles into?
C)Gold

2.When Thomson held a positively charged plate near the cathode ray, the beam bent toward the plate. What conclusion can be drawn from this observation?
C)The beam was negatively charged.

3.)What was observed during Rutherford's experiment?
D)Most of the particles went through the foil, but some were deflected.</span>

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The strongly polar, hydrogen-bonding properties of water make it an excellent solvent for ionic (charged) species. By contrast,

trapecia [35]

Answer:

hello your question is incomplete attached below is the complete question

Pyridinium ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.

N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while

B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion

Explanation:

Pyridine ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.

N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while

B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion

attached below is the remaining part of the solution

7 0

4 years ago

Question 10

creativ13 [48]

Answer:

M₂ = 0.08 M

Explanation:

Given data:

Initial volume = 25.0 mL

Initial molarity = 0.500 M

Final volume = 150.0 mL

Final molarity = ?

Solution:

Formula:

M₁V₁ = M₂V₂

0.500 M × 25.0 mL = M₂ × 150.0 mL

M₂ = 0.500 M × 25.0 mL / 150.0 mL

M₂ = 12.5 M.mL /150.0 mL

M₂ = 0.08 M

5 0

3 years ago

3.0 L of a gas has a temperature of 78 C find the volume of the gas at standard temperature

jeka57 [31]

Answer:

= 2.33 L

Explanation:

V1/T1 = V2/T2

V1 = 3.0 L

T1 = 78 + 273

= 351 K

At s.t.p the temperature is 273 K and pressure is 1 atm.

V2 = ?

T2 = 273 K

V2 = V1T2/T1

= (3.0 ×273)/351

= 2.33 L

Explanation:

ik it is confusing but that is what i got

4 0

3 years ago

Read 2 more answers

Phosphorus pentachloride decomposes at higher temperatures. PCl5(g) ⇄ PCl3(g) + Cl2(g) An equilibrium mixture at some temperatur

aliya0001 [1]

Answer:

The reaction shifts from right to left. The new concentration of PCl₅ in equilibrium is 1.133 M.

Explanation:

The stress applied to the system is the addition of Cl₂. To offset this stress, <u>some Cl₂ reacts with PCl₃ to produce PCl₅ until a new equilibrium is established</u>.

The net reaction therefore shifts from right to left, that is,

PCl₅ (g) ← PCl₃ (g) + Cl₂ (g)

To work with the Kc expression, we need to convert the grams to moles. Since the volume of the flask is 1 liter, the moles can be expressed as molarity.

For PCl₅:

208.23 g ---------- 1 mol

3.74 g -------------- x= 1.80 x10⁻² mol ⇒ 1.80 x10⁻² M

For PCl₃:

137.33 g ---------- 1 mol

4.86 g ------------- x= 3.54 x10⁻² mol ⇒ 3.54 x10⁻² M

For Cl₂:

70.91 g ---------- 1 mol

3.59 g ----------- x= 5.06 x10⁻² mol ⇒ 5.06 x10⁻² M

Now, taking into account the shift of the equation, we make an ICE chart:

PCl₅ (g) ← PCl₃ (g) + Cl₂ (g)

i) 1.80 x10⁻² 3.54 x10⁻² 5.06 x10⁻²

c) +x -x +1.31 x10⁻² -x

e) 1.80 x10⁻² +x 3.54 x10⁻² -x 5.06 x10⁻²+1.31 x10⁻² -x

Now, we write the Kc formula:

Kc = [PCl₃] [Cl₂] / [PCl₅]

Kc = [ 3.54 x10⁻² -x] [5.06 x10⁻²+1.31 x10⁻² -x] / [1.80 x10⁻² +x]

After working with the expression, we find that x = 1.115.

Therefore, the new concentration of PCl₅ will be 1.133 M.

7 0

3 years ago

Read 2 more answers

Look at the graph of reaction rate versus substrate concentration for an enzyme. In which region does the reaction rate remain c

OleMash [197]

Answer:

The correct answer is C.

Explanation:

The reaction speed remains constant in region C. This is because the growth rate decreases, tending to zero. Graphically you can see how the slope of the tangent line approaches the horizontal. The slope of the tangent line represents the rate of reaction speed. It is constant because although the concentration continues to increase, the reaction rate does not vary.

Have a nice day!

6 0

4 years ago