This question is incomplete, the complete question is;
The area of the gold electrodes on the quartz crystal microbalance at the opening of Chapter 2 is 3.3 mm^2. One gold electrode is covered with DNA at a surface density of 1.2 pmol/cm2.
(a) How much mass of the nucleotide cytosine (C) is bound to the surface of the electrode when each bound DNA is elongated by one unit of C. The mass formula mass of the bound nucleotide is cytosine + deoxyribose + phosphate = C9H10N3O6P = 287.2 g/mol
Answer: mass of the nucleotide (c) bound is 11.37 g
Explanation:
Given that the area of gold electrodes = 3.3 mm^2
surface density of one gold electrode = 1.2 pmol/cm^2
that is to that in every 1 cm^2 of area, 1.2 pmol DNA is present
therefore
mass of nucleotide present in 3.3 mm^2 is;
= (1.2/100 * 3.3) pmol
= 0.0396 pmol
we were given that formula mass of the bound nucleotide = 287.2 g/mol
so
mass of the nucleotide (c) bound = ( 287.2 * 0.0396 )g
mass of the nucleotide (c) bound = 11.37 g
Answer:
molar mass HA = 87.8 g/mole
Explanation:
Given 0.140g HA + 14.5ml(0.110M NaOH) => NaA + H₂O
Rxn is a 1:1 rxn ration => moles HA neutralized = moles NaOH used
=> 0.140g/molar mass of HA = (0.110M)(0.0145L)
=> molar mass of HA = (0.140g)/[(0.110moles/L)(0.0145L)] = 87.8 g/mole
The name isovolumetric indicates that there is no change in volume that takes place and this only occurs when all of the valves within the heart are shut.
Equilibrium concentration of SO3=1.7M
Equilibrium concentration of SO2=0.070 M
Equilibrium concentration of NO2=1.3 M
Equilibrium constant is given as=10.8
The equilibrium reaction is given as:
SO2(g)+NI2(g)⇌NO(g) +SO3(g)
Keq= ([NO][SO3])/([SO2][NO2])
To calculate concentration of NO rearranging the above equation will give:
NO=Keq*[SO2][NO2]/[SO3]
NO=(10.8*0.070*1.3)/1.7
= 0.578M
So concentration of NO will be 0.578M
This is your answer white blood cells (WBC)