Answer:
Solubility = [SO₄²⁻]
Explanation:
Solubility of Ag₂SO₄ can be understood seen its Ksp equilibrium:
Ag₂SO₄(s) ⇄ SO₄²⁻ + 2Ag⁺
<em>Where 1 mole of silver sulfate dissolves producing 1 mole of sulfate ion and 2 moles of silver ion.</em>
Solubility is defined as: "the amount of solid that can be dissolved per liter of solution".
In the dissolution process, the moles of Ag₂SO₄ dissolved are equal to moles of SO₄²⁻.
That means:
<h3>Solubility = [SO₄²⁻]</h3>
As you go down the table, more electron shells are added to make the radius larger, but as you go to the right, the protons' attraction increases so the radius actually shrinks. <span>Therefore, according to the trend, Cl has a larger radius because it is lower in the table.</span>
Answer: CL has a larger Atomic Radius.
It would be none would it not
Answer:
ΔH = ΔH₁ + ΔH₂ - ΔH₃
Explanation:
Given that:
1. A → 2B
2. B → C + D
3. E → 2D
Assuming from the corresponding ΔH for process 1, 2 and 3 are ΔH₁, ΔH₂, ΔH₃ respectively.
To estimate the ΔH for the process A → 2C + E
We multiply 2 with equation 2 where (B → C + D)
2B → 2C + 2D ⇒ 2ΔH₂
Also, let's switch equation (3), such that we have,
2D → E -ΔH₃
The summation of all the equation result into :
A → 2C + E
where; ΔH = ΔH₁ + ΔH₂ - ΔH₃
