Depth and salinity are the two factors that make the seawater different
Answer:
unbalanced moving to the right is the awnser
Answer:
<u><em>PLEASE SHOW ME THE ELEMENTS OR I WOULD ENLIST ALL THE ELEMENTS.</em></u>
Explanation:
Group 6A (or VIA) of the periodic table are the chalcogens: the nonmetals oxygen (O), sulfur (S), and selenium (Se), the metalloid tellurium (Te), and the metal polonium (Po)
Using Hess' Law, we can calculate the heat of reaction of the gasification of coal. Multiplying the second reaction by 2 and reversing the third reaction:
<span>C(s) + O2(g) → CO2(g) ∆H=-394 kj
2H2(s) + O2(g) → H2O(l) ∆H=-572kj
</span>CO2(g) + 2H2O(l) → CH4(g) + 2O2(g) ∆H=891kj
Adding the three reaction would result to
<span>C(s) + 2H2(g) → CH4(g) ∆H = -394 + -572 + 891 = -75 kJ
The answer is
</span><span>(B) -75 kJ
</span>
Answer: The final temperature (T) will be;
16.23°c
Explanation: To find the final temperature of any mixture of substance with an initial temperature use the formula;
M1c(T-T1) + M2c(T-T2)=0
c is the specific heat capacity of the two different substance, but because ice and water are the same, we assume c to be 1
T= final temperature of the mixture
T1= initial temperature of the ice= -10.2°c
T2= initial temperature of the water= 19.7°c
M1= mass of ice= 33.1g
M2= mass of water= 251g
Using the formula above
33.1(T-(-10.2)) + 251(T-19.7)=0
Solving out the bracket
33.1T + 337.62 + 251T - 4944.7 = 0
Collecting like terms to both side of the equation and solving
33.1T + 251T = 4944.7 - 33.62
284.1T = 4607.08
T = 4607.08÷284.1 = 16.23°c
