Answer:
C M (change in T) = heat absorbed thermal equation for heat gained
C = 418.4 J / (2 kg * 50 deg K) = 4.184 J / kg * deg K specific heat
Note: 1 gm =.001 kg
So C = .004184J / gm * deg K
Also, 1 J = .239 cal so in conventional terms
C = .001 cal / gm deg K (very low, water would be 1 cal / gm deg C
Answer:
2442.5 Nm
Explanation:
Tension, T = 8.57 x 10^2 N
length of rope, l = 8.17 m
y = 0.524 m
h = 2.99 m
According to diagram
Sin θ = (2.99 - 0.524) / 8.17
Sin θ = 0.3018
θ = 17.6°
So, torque about the base of the tree is
Torque = T x Cos θ x 2.99
Torque = 8.57 x 100 x Cos 17.6° x 2.99
Torque = 2442.5 Nm
thus, the torque is 2442.5 Nm.
The average speed of Frank's car is 2 m/s and the average speed of Noah's car is 1.8 m/s.
<u>Explanation:</u>
Average speed is the measure of total distance covered at different time period. Since, the formula used for calculating the average speed is the ratio of total distance covered by each car to the time taken to cover that distance.
As there is only one set of data i.e., distance and time, the average speed will be equal to the speed of the car.
So in this case, the total distance covered by franks car is 300 cm = 3 m in 1.5 s. Then, the average speed will be
Similarly, the average speed of Noahs car which rolled a distance of 360 cm = 3.6 m in time 2 s, will be
Thus, the average speed of Frank's car is 2 m/s and the average speed of Noah's car is 1.8 m/s.
Answer:
A. Atom :- a substance that cannot be broken down into a simpler substance.
Explanation:
Atom is a basic unit of any chemical substance or element. It cannot be broken into simpler material. Although it is known that an atom is made up of electron proton and neutron but these are not simpler substances. In an atom electron is negatively charged and proton is positively, while neutron is neutral.
Answer:
Explanation:
q = 2e = 3.2 x 10^-19 C
mass, m = 6.68 x 10^-27 kg
Kinetic energy, K = 22 MeV
Current, i = 0.27 micro Ampere = 0.27 x 10^-6 A
(a) time, t = 2.8 s
Let N be the alpha particles strike the surface.
N x 2e = q
N x 3.2 x 10^-19 = i t
N x 3.2 x 10^-19 = 0.27 x 10^-6 x 2.8
N = 2.36 x 10^12
(b) Length, L = 16 cm = 0.16 m
Let N be the alpha particles
K = 0.5 x mv²
22 x 1.6 x 10^-13 = 0.5 x 6.68 x 10^-27 x v²
v² = 1.054 x 10^15
v = 3.25 x 10^7 m/s
So, N x 2e = i x t
N x 2e = i x L / v
N x 3.2 x 10^-19 = 2.7 x 10^-7 x 0.16 / (3.25 x 10^7)
N = 4153.85
(c) Us ethe conservation of energy
Kinetic energy = Potential energy
K = q x V
22 x 1.6 x 10^-13 = 2 x 1.5 x 10^-19 x V
V = 1.17 x 10^7 V
