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marshall27 [118]

2 years ago

10

Please read the short case at the end of Chapter 8, "Mary Barra of General Motors Values Culture". Use the following prompts to

start thinking about the case and the chapter materials. Post your thoughts to the discussion, making sure to consider the requirements in the Grading Rubric. PLEASE DO NOT REPLY TO ALL THE QUESTIONS BELOW IN ONE POST! These questions are just meant to get you thinking-- you do not need to address each question in one post.

1 answer:

Tom [10]2 years ago

4 0

Answer: Incoherent question

Explanation: This is an act of plagiarism at subjecting the tutor to unnecessary stress at answering the purported question.

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Lick the bullet and push it down

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2 years ago

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g Part 2: The features arrived the grammar Splitting categories and non-terminals gets out of hand fast. An alternative to the p

koban [17]

Answer:

The split is given by including spaces in both tabs

Explanation:

The bracket notation can be used to indicate the split. Here is an example:

String [ ] parts = s. split ( "[/]")

3 0

2 years ago

An electromagnet is formed when a coil of wire wrapped around an iron core is hooked up to a dry cell battery. The current trave

german

Answer:

true

Explanation:

true An electromagnet is formed when a coil of wire wrapped around an iron core is hooked up to a dry cell battery. The current traveling through the wire sets up a magnetic field around the wire. TRUE or FALSE

3 0

2 years ago

A spacecraft at rest has moment of inertia of 100 kg-m^2 about an axis of interest. If a 1 newton thruster with a 1 meter moment

Kazeer [188]

To solve this problem we will apply the concepts related to translational torque, angular torque and the kinematic equations of angular movement with which we will find the angular displacement of the system.

Translational torque can be defined as,

$\tau = Fd$

Here,

F = Force

d = Distance which the force is applied

$\tau = (1N)(1m)$

$\tau = 1N\cdot m$

At the same time the angular torque is defined as the product between the moment of inertia and the angular acceleration, so using the previous value of the found torque, and with the moment of inertia given by the statement, we would have that the angular acceleration is

$\tau = I\alpha$

$\alpha = \frac{\tau}{I}$

$\alpha = \frac{1N\cdot m}{100kg\cdot m^2}$

$\alpha = 0.01rad/s^2$

Now the angular displacement is

$\theta = \omega_0 t + \frac{1}{2}\alpha t^2$

Here

$\omega_0$ = Initial angular velocity

t = time

$\alpha =$ Angular acceleration

$\theta$ = Angular displacement

Time is given as 1 minute, in seconds will be

$t = 1m = 60s$

There is not initial angular velocity, then

$\theta= \frac{1}{2}\alpha t^2$

Replacing,

$\theta= \frac{1}{2}(0.01)(60)^2$

$\theta = 18rad$

The question neglects the effect of gravitational force.

4 0

2 years ago

: During a heavy rainstorm, water from a parking lot completely fills an 18-in.- diameter, smooth, concrete storm sewer. If the

Montano1993 [528]

Answer

diameter of parking lot = 18 in

flowrate = 10 ft³/s

pressure drop = 100 ft

using general equation

$\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g}+Z_1 = \dfrac{P_2{\gamma} + \dfrac{v_2^2}{2g} + Z_2 +\dfrac{fLV^2}{2\rho D}$

$V = \dfrac{Q}{A} = \dfrac{10}{\dfrac{\pi}{4}(\dfrac{18}{12})^2} = 5.66\ ft/s$

$\Delta P = \gamma (Z_2-Z_1) +\dfrac{fLV^2}{2\rho D}$

taking f = 0.0185

at Z₁ = Z₂

$\Delta P = \dfrac{0.0185 \times 100\times 1.94\times 5.66^2}{2\dfrac{18}{12} (2)}$

ΔP = 0.266 psi

b) when flow is uphill z₂-z₁ = 2

$\Delta P =62.4\times 2 \times \dfrac{1}{144} +0.266$

$\Delta P= 1.13\ psi$

c) When flow is downhill z₂-z₁ = -2

$\Delta P =62.4\times 2 \times \dfrac{1}{144} +0.266$

$\Delta P=-0.601\ psi$

7 0

2 years ago