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bonufazy [111]
4 years ago
8

According to Newton’s third law of motion, what happens whenever one object exerts a force on a second object?

Physics
1 answer:
mixas84 [53]4 years ago
6 0

Answer:

When one object exerts a force on another object, the second object exerts the same size force on the first object

Explanation:

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How many ohms of resistance must be present in a circuit that has 240 volts and a current of 15 amps?
PIT_PIT [208]

Answer:

16 ohms

Explanation:

V= I ⋅ R

where,  V  is the net potential difference in the circuit,  I  is the current in the circuit and  R  is the net resistance of the circuit.  

In this case,  V = 240  volts,  I = 15  amperes.

240 = 15 ⋅ R  

⇒ R = 240/ 15 = 16  ohms

5 0
3 years ago
Read 2 more answers
A roller coaster is released from the top of a track that is 57 m high. Find the roller coaster speed when it reaches ground lev
Art [367]

Hi there!

Assuming the track is frictionless:

E_i = E_f\\\\PE = KE\\\\mgh = \frac{1}{2}mv^2

Cancel out the masses and rearrange to solve for velocity:

gh = \frac{1}{2}v^{2}\\\\v = \sqrt{2gh}\\\\

Plug in the given height and let g = 9.8 m/s²:

v = \sqrt{2(9.8)(57)} = \boxed{33.42 m/s}

7 0
3 years ago
If you push a book against a wall hard enough, it will not slide down even though gravity is pulling it. Use what you know about
Rashid [163]

The frictional force is too much compared to the gravitational force

Explanation:

This is because of the great amount of frictional force between the book and the wall.

Also, the force of gravity on the book is not high enough to cause motion of the book to slide downs.

Frictional force is a force that opposes motion.

  • For the book to slide down, it must overcome the force of friction acting on it opposite to the direction of gravity.
  • According to newton's first law 'a body will remain in its state of rest or uniform motion unless acted upon by an external force'.
  • Assuming the external force is gravitational force, clearly we see that the force is less than the frictional exerted on the book by pinning it to the wall.
  • This frictional force is a static friction that is on a body at rest, it must be overcome by a larger force before motion takes place.

           Fr  >  fg

Fr is the frictional force

fg is the gravitational force

learn more:

Newton laws brainly.com/question/11411375

#learnwithBrainly

3 0
4 years ago
What is the net torque on the square plate, with sides 0.2 m, from each of the three forces? F1=18 N, F2=26 N, and F3=14 N. Use
marshall27 [118]

Answer:

The net torque on the square plate is 2.72 N-m.

Explanation:

Given that,

Side = 0.2 m

Force F_{1}=18\ N

Force F_{2}=26\ N

Force F_{3}=14\ N

We need to calculate the torque due to force F₁

Using formula of torque

\tau_{1}=-F_{1}d_{1}

\tau_{1}=-F_{1}\times\dfrac{a}{2}

Put the value into the formula

\tau_{1}=-18\times\dfrac{0.2}{2}

\tau_{1}=-1.8\ N-m

We need to calculate the torque due to force F₂

Using formula of torque

\tau_{2}=F_{2}d_{2}

\tau_{2}=F_{2}\times\dfrac{a}{2}

Put the value into the formula

\tau_{2}=26\times\dfrac{0.2}{2}

\tau_{2}=2.6\ N-m

We need to calculate the torque due to force F₃

Using formula of torque

\tau_{3}=F_{3}d_{3}

\tau_{3}=(F_{3}\sin45+F_{3}\cos45)\times\dfrac{a}{2}

Put the value into the formula

\tau_{3}=0.1(14\sin45+14\cos45)

\tau_{3}=1.92\ N-m

We need to calculate the net torque on the square plate

\tau=\tau_{1}+\tau_{2}+\tau_{3}

\tau=-1.8+2.6+1.92

\tau=2.72\ N-m

Hence, The net torque on the square plate is 2.72 N-m.

3 0
4 years ago
PLEASE HELP I WILL GOVE BRAINLIEST TO FIRST CORRECT ANSWER!!!!!
Dmitrij [34]
Answer is C is the correct answer
8 0
4 years ago
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