Question

A buret was improperly read to 1 decimal place giving a reading of 27.2 mL. If the actual volume is 27.26 mL, what is the percent error caused by this mistake?

Answer 1

Answer: 0.22 %

Explanation:

Actual volume : 27.26 ml

Volume measured : 27.2 ml

$\% error=\frac{|\text{(Experimental value - theoretical value)|}}{\text{theoretical value}}\times 100$

Putting the values we get:

$\%=\frac{|\text{(27.26- 27.2)|}}{27.26}\times 100=0.22\%$

Thus the percent error caused by this mistake is 0.22%

Answer 2

Percent error can be calculated by the difference of the theoretical value and the measured value divided by the theoretical value multiplied by 100 percent. 

% error = 27.26 - 27.2 / 27.26 x100
% error = 0.22%

A value close to zero would mean that the measured value is more or less near the actual value.