In track, there is a 1500 meter event. Is this distance more or less than a mile?

A large man sits on a four-legged chair with his feet off the floor. The combined mass of the man and chair is 95.0 kg. If the c

Leto [7]

Answer:

Pressure, $P=29.6\times 10^5\ Pa$

Explanation:

It is given that,

Combined mass of the man and the chair, m = 95 kg

Radius of the leg of chair, r = 0.5 cm = 0.005 m

A large man sits on a four-legged chair with his feet off the floor. The force acting per unit area is called the pressure exerted.

$P=\dfrac{F}{A}$

$P=\dfrac{mg}{A}$

Area of 4 legs, A = 4 A

$P=\dfrac{mg}{4\pi r^2}$

$P=\dfrac{95\times 9.8}{4\pi (0.005)^2}$

$P=29.6\times 10^5\ Pa$

So, the pressure each leg exert on the floor is $29.6\times 10^5\ Pa$ . Hence, this is the required solution.

7 0

3 years ago

What word does this define..<br><br>The distance traveled per unit of time

nexus9112 [7]

Answer:..........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................Volosity???????

Explanation: THINK THATS IT PROBABLY MISPELLED IT SORRY IN ADVANCE IF WRONG

8 0

3 years ago

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William Tell shoots an apple from his son's head. The speed of the 102-g arrow just before it strikes the apple is 26.7 m/s, and

xxMikexx [17]

To develop the problem, we require the values concerning the conservation of momentum, specifically as given for collisions.

By definition the conservation of momentum tells us that, $m_1V_1+m_2V_2 = (m1+m2)V_f$

To find the speed at which the arrow impacts the apple we turn to the equation of time, in which,

$t= \sqrt{\frac{2h}{g}}$

The linear velocity of an object is given by

$V=\frac{X}{t}$

Replacing the equation of time we have to,

$V_f = \frac{X}{t}\\V_f =\frac{X}{\sqrt{\frac{2h}{g}}}\\V_f = \frac{6.9}{\sqrt{\frac{2(1.85)}{9.8}}}\\V_f = 11.23m/s$

Velocity two is neglected since there is no velocity of said target before the collision, thus,

$m_1V_1 = (m1+m2)V_f$

Clearing for m_2

$m_2 = \frac{m_1V_1}{V_f}-m_1\\m_2 = \frac{(0.102)(26.7)}{11.23}-0.102\\m_2 = 0.1405KG= 140.5g$

8 0

3 years ago

What will happen to this current if a magnet is brought near the cord? A. It will exert a force on the voltage. B. The electric

Andreyy89

Answer:

The correct answer is D)

Explanation:

When an electric magnet is brought near a cord with an electric current, the cord will most likely deflect away from the magnet because electric fields flowing through a wire generates its own magnetic field.

Cheers!

8 0

3 years ago

The forces acting on a sailboat are 390. N south and 180. N east. If the boat (including

velikii [3]

Answer:

180^2 + 390^2 = force ^2 (Pythagoras) root of force^2 = 429.5N approx resultant force Acceleration = Force/Mass 429.5/270 = 1.5907 ms^-2 in a Southwesterly direction.

Explanation:

4 0

3 years ago