Answer:
Heat required to raise the temperature of the aluminium is 4750 J
Explanation:
As we know that the heat energy required to raise the temperature of the aluminium is given as
![Q = ms\Delta T](https://tex.z-dn.net/?f=Q%20%3D%20ms%5CDelta%20T)
here we know that
m = 50 g
![\Delta T = 110 - 10](https://tex.z-dn.net/?f=%5CDelta%20T%20%3D%20110%20-%2010)
![\Delta T = 100 ^oC](https://tex.z-dn.net/?f=%5CDelta%20T%20%3D%20100%20%5EoC)
so we have
![Q = 50(0.95)(100)](https://tex.z-dn.net/?f=Q%20%3D%2050%280.95%29%28100%29)
![Q = 4750 J](https://tex.z-dn.net/?f=Q%20%3D%204750%20J)
If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C
<u>Given the following the details;</u>
- Electric potential = 8 Volts
To find the quantity of charge;
Mathematically, the quantity of charge with respect to electric potential is given by the formula;
![Quantity \; of \; charge = \frac{Energy}{Electric \; potential}](https://tex.z-dn.net/?f=Quantity%20%5C%3B%20of%20%5C%3B%20charge%20%3D%20%5Cfrac%7BEnergy%7D%7BElectric%20%5C%3B%20potential%7D)
Substituting the values into the formula, we have;
![Quantity \; of \; charge = \frac{40}{8}](https://tex.z-dn.net/?f=Quantity%20%5C%3B%20of%20%5C%3B%20charge%20%3D%20%5Cfrac%7B40%7D%7B8%7D)
<em>Quantity of charge = 5 Coulombs</em>
Therefore, the quantity of charge must be <em>5 Coulombs.</em>
Find more information: brainly.com/question/21808222
Answer:
is it 3?
Explanation:
Im taking a guess and just dividing 6 and 2
Hi there!
We can use Newton's Second Law:
![\Sigma F = ma](https://tex.z-dn.net/?f=%5CSigma%20F%20%3D%20ma)
ΣF = Net force (N)
m = mass (kg)
a = acceleration (m/s²)
We can rearrange the equation to solve for the acceleration.
![a = \frac{\Sigma F}{m}\\\\a = \frac{24}{4} = \boxed{6 \frac{m}{s^2}}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%5CSigma%20F%7D%7Bm%7D%5C%5C%5C%5Ca%20%3D%20%5Cfrac%7B24%7D%7B4%7D%20%3D%20%5Cboxed%7B6%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%7D)
Answer:
her displacement <em>s=337.5m</em>
Explanation:
check out the above attachment ☝️