The Ancient Egyptians used simple sundials and divided days into smaller parts, and it has been suggested that as early as 1,500BC, they divided the interval between sunrise and sunset into 12 parts. ... Known as a clepsydra, it uses a flow of water to measure time.
Answer : The heat energy absorbed will be, 
Solution :
The process involved in this problem are :

The expression used will be:
![\Delta H=m\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]](https://tex.z-dn.net/?f=%5CDelta%20H%3Dm%5Ctimes%20%5CDelta%20H_%7Bfusion%7D%2B%5Bm%5Ctimes%20c_%7Bp%2Cl%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D)
where,
m = mass of ice = 1100 g
= specific heat of liquid water = 
= enthalpy change for fusion = 
Molar mass of water = 18 g/mole
Now put all the given values in the above expression, we get:
![\Delta H=1100g\times 333.89J/g+[1100g\times 4.18J/g^oC\times (32.0-0)^oC]](https://tex.z-dn.net/?f=%5CDelta%20H%3D1100g%5Ctimes%20333.89J%2Fg%2B%5B1100g%5Ctimes%204.18J%2Fg%5EoC%5Ctimes%20%2832.0-0%29%5EoC%5D)

Conversion used : (1 cal = 4.184 J)
Therefore, the heat energy absorbed will be, 