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Elis [28]
3 years ago
9

How many moles of Mgs203 are in 245g of the compound

Chemistry
1 answer:
marishachu [46]3 years ago
7 0
Molecular weight of MgSO3 = 104.3682 g/mol
181 g / 104.3682 g/mol
= 1.73 g
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Which two particles in an atom are equal in mass
Taya2010 [7]
Protons and neutrons.

Note: They probably are ABOUT the same mass. Don't think they are exactly the same.

Hope this helps! 
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3 years ago
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What is silica gel commonly used for? A. Absorbing moisture to protect goods from damage. B. As insulation in buildings. C. As a
omeli [17]

Answer:

A

Explanation:

5 0
2 years ago
How many moles of water would form the reaction of exactly 58.3 grams of magnesium hydroxide
Marat540 [252]

Answer:

\boxed{\text{2.00 mol}}

Explanation:

We know we will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

You don't tell us what the reaction is, but we can solve the problem so long as we balance the OH.

M_r:      58.32

          Mg(OH)₂ + … ⟶ … + 2HOH

m/g:       58.3

(a) Moles of Mg(OH)₂

\text{Moles of Mg(OH)$_{2}$} =\text{58.3 g Mg(OH)$_{2}$} \times \dfrac{\text{1 mol Mg(OH)$_{2}$}}{\text{58.32 g Mg(OH)$_{2}$}}\\\\=\text{0.9997 mol Mg(OH)$_{2}$}

(b) Moles of H₂O

The molar ratio is 2 mol H₂O = 1 mol Mg(OH)₂.

\text{Moles of H$_{2}$O}= \text{0.9995 mol Mg(OH)$_{2}$} \times \dfrac{\text{2 mol {H$_{2}$O}}}{ \text{1 mol Mg(OH)$_{2}$}}\\\\= \textbf{2.00 mol H$_{2}$O}

The reaction will form \boxed{\textbf{2.00 mol}} of water.

6 0
3 years ago
What are the source of error in determination of boiling point and melting point
Neko [114]
<span> purity of the substance is usually the main error (for example: water with impurities will have m.p. less than 273K or 0 degree celcius while it's b.p. will be greater than 373K or 100 degree celcius). </span>
<span>-> air/ room temperature (it takes longer to cook in mountains and shorter at beaches) </span>
<span>-> parallax error (error by determining the meniscus of the thermometer) </span>
<span>and many more..</span>
7 0
2 years ago
Show the relationship of number of moles and volume in Avogadro's law using data. Write your calculations and answer on a separa
leonid [27]

Answer:

See below ~

Explanation:

The calculated values of V/n :

⇒ 1.5/0.3 = 5

⇒ 3/0.6 = 5

⇒ 4.5/0.9 = 5

⇒ 6/1.2 = 5

⇒ 7.5/1.5 = 5

1. From this we understand that the calculated values of V/n remain constant, equal to <u>5</u> in this case.

2. The volume-mole graph will be a straight line passing through the origin. (Attached below)

7 0
1 year ago
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