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Nadusha1986 [10]
3 years ago
11

Given a books table with columns named book_title and year_released, the following SQL statement will select the number of books

released each year. SELECT book_title, year_released FROM books GROUP BY year_released;
Engineering
1 answer:
lord [1]3 years ago
8 0

Question Continuation

True or False?

Answer:

False

Explanation:

Given

Columns: book_title and year_released

SQL statement: SELECT book_title, year_released FROM books GROUP BY year_released

Expected Result: To select the number of books released each year

Although the GROUP BY used in the SQL statement is meant to group rows with same values into summary rows but it's not user properly because the GROUP BY clause, as used here needs the COUNT aggregate functions to group the result-set by one or more columns.

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g A circular oil slick of uniform thickness is caused by a spill of one cubic meter of oil. The thickness of the oil slick is de
Anika [276]

Answer:

the rate of increase of radius is dR/dt = 0.804 m/hour = 80.4 cm/hour

Explanation:

the slick of oil can be modelled as a cylinder of radius R and thickness h, therefore the volume V is

V = πR² * h

thus

h = V / (πR²)

Considering that the volume of the slick remains constant, the rate of change of radius will be

dh/dt = V d[1/(πR²)]/dt

dh/dt = (V/π) (-2)/R³ *dR/dt

therefore

dR/dt = (-dh/dt)* (R³/2) * (π/V)

where dR/dt = rate of increase of the radius , (-dh/dt)= rate of decrease of thickness

when the radius is R=8 m , dR/dt is

dR/dt = (-dh/dt)* (R³/2) * (π/V) = 0.1 cm/hour *(8m)³/2 * π/1m³ *(1m/100 cm)= 0.804 m/hour = 80.4 cm/hour

4 0
3 years ago
SAHARA<br>Jeep<br>WRANGLES<br>G​
koban [17]

Answer:

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8 0
2 years ago
For this problem, calculate the following by hand and show the procedure for how you obtained the results. Subsequently, solve p
Gemiola [76]

Answer:wat

Explanation:

4 0
3 years ago
A storage tank, used in a fermentation process, is to be rotationally molded from polyethylene plastic. This tank will have a co
NNADVOKAT [17]

Answer:

The volume up to cylindrical portion is approx  32355 liters.

Explanation:

The tank is shown in the attached figure below

The volume of the whole tank is is sum of the following volumes

1) Hemisphere top

Volume of hemispherical top of radius 'r' is

V_{hem}=\frac{2}{3}\pi r^3

2) Cylindrical Middle section

Volume of cylindrical middle portion of radius 'r' and height 'h'

V_{cyl}=\pi r^2\cdot h

3) Conical bottom

Volume of conical bottom of radius'r' and angle \theta is

V_{cone}=\frac{1}{3}\pi r^3\times \frac{1}{tan(\frac{\theta }{2})}

Applying the given values we obtain the volume of the container up to cylinder is

V=\pi 1.5^2\times 4.0+\frac{1}{3}\times \frac{\pi 1.5^{3}}{tan30}=32.355m^{3}

Hence the capacity in liters is V=32.355\times 1000=32355Liters

3 0
3 years ago
A controlled process is described by the closed-loop transfer function G(s).
MissTica

Answer:

The answer is "Option B".

Explanation:

Given equation:

G(s) =\frac{K(s + 1)}{2s^2 + (K-1)s + (K-1)}\\\\

if

\to 2s^2 + (K-1)s + (K-1)=0

Calculating by the Routh's Hurwitz table:

\to s^2  \ \ \ \ \    2  \ \ \ \ \ \  K-1 \\\\\to s^2  \ \ \ \ \    K-1  \ \ \ \ \ \   \\\\\to s^0 \ \  ( \frac{(K-1)(K-1)(-2) (0)}{K-1}  \\\\    \ \ \ \  = (K-1) )

Form the above table:

\to K-1 > 0 \\\\ \to K > 1

In the above, the value of k is greater than 1.

3 0
3 years ago
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