Answer:
Kinetic Enerrgy = 12744000 J or 12.744 MJ
Explanation:
Given Data:
Mass of fragment = m =1770 kg ;
Estimated speed = v = 120 m/sec ;
Solution:
As we know that
Kinetic energy = K.E = (1/2)mv²
By putting the values, we get
K.E = 0.5*1770*120²
K.E = 12744000 J
or
K.E = 12.744 MJ
So, the kinetic energy of lead-lined vault when it landed was 12.744MJ approximately.
1) Hubble Space Telescope- Visible and near-ultraviolet
2) Compton Gamma Ray Observatory- Gamma Rays
3) Chandra X-ray Observatory- X-rays
4) Spitzer Space Telescope- infrared
Answer:
when an object kept at some height and having some mass then ,when it falls down then shifting of energy takes place
Her speed was 7.27 meters per second
