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goblinko [34]
3 years ago
14

In quantum mechanics, the fundamental constant called Planck's constant, h, has dimensions of [ML^2T^-1 ]. Construct a quantity

with the dimensions of length using h, a mass m, and c, the speed of light.
Physics
1 answer:
Mice21 [21]3 years ago
4 0

Answer:

h/(m*c)

Explanation:

Hi!

Lets denote the units of X as [X]

Since the dimentions of h are:

[h] = \frac{ML^{2}}{T}

If we divide [h] by the units of mass, we get:

\frac{[h]}{[m]} = \frac{L^{2}}{T}}

Also we know that:

[c] = \frac{L}{T}

So:

[\frac{h}{mc}] = \frac{L^{2}}{T}}*\frac{T}{L}=L

Therefore

 h/(mc) has dimentiosn of length

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Answer:

The mass of the object is 5.045 lbm.

Explanation:

Given;

kinetic energy of the object, K.E = 1558.71 ft.lbf

velocity of the object, V = 141 ft/s

The kinetic energy of the object is calculated as;

K.E = \frac{1}{2} mV^2\\\\mV^2 = 2K.E\\\\m = \frac{2K.E}{V^2} \\\\1 \ lbf = 32.174 \ lbm.ft/s^2\\\\m  = \frac{2 \ \times \ 1558.71 \ ft.lbf \ \times \ 32.174 \ lbm.ft/s^2 }{(141 \ ft/s)2 \ \  \times \ \ \ \ 1   \ lbf\ }

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Therefore, the mass of the object is 5.045 lbm.

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