Question

Crossed electric and magnetic fields are established over a certain region. The magnetic field is 0.669 T vertically downward. The electric field is 2.64 x 106 V/m horizontally east. An electron, traveling horizontally northward, experiences zero net force from these fields and so continues moving in a straight line. What is the electron's speed

Answer 1

Answer:

The speed  is $v = 3.946 *10^6 \ m/s$

Explanation:

From the question we are told that

     The magnetic  field is  $B = 0.669\ T$

      The electric field is  $E = 2.64 *10^{6} \ V/m$

     

Generally the speed of the electron is mathematically represented as

               $v = \frac{E}{B}$

    Substituting values

                $v = \frac{2.64 *10^6}{0.669}$

                $v = 3.946 *10^6 \ m/s$