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Alja [10]
3 years ago
13

Use the mean value off Keq to calculate the SCN- concentration in a solution whose initial Fe3+ concentration was 4.00x10^-2 M (

.04M) and initial SCN- concentration was 1.00x10^-3M (.001M).
Is all the SCN- in the form of FeNCS2+? Mean Value = 48. Solved for SCN- concentration = 0.0006538

Does the result of the calculation justify our original assumption that all of the SCN- is in the form of FeNCS^2+?
Chemistry
1 answer:
Colt1911 [192]3 years ago
8 0
So the problem ask to justify that does the result of the calculation justify the original assumptions that all of the SCN is the form of FeNCS^2 and the best way to prove it is that both of them has a relative measurement percentage of 37.681%. I hope this helps
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Answer: The osmotic pressure of a solution is 53.05 atm

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (methanol) = 22.3 g  

Volume of solution = 321 mL

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

\pi=1\times \frac{22.3\times 1000}{32.04\times 321}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K

\pi=53.05atm

Hence, the osmotic pressure of a solution is 53.05 atm

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