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Vinvika [58]
3 years ago
8

In the Niagara Falls hydroelectric generating plant, the energy of falling water is converted into electricity. The height of th

e falls is about 48 meters. Assuming that the energy conversion is highly efficient, approximately how much energy is obtained from one kilogram of falling water? Therefore, approximately how many kilograms of water must go through the generators every second to produce a megawatt of power (106 watts)?
Physics
1 answer:
Tamiku [17]3 years ago
3 0

Answer:

2.124 kg of water

Explanation:

height of the falls is about 48 meters.

Mass of water needed is 1kg = 1000g

Power needed is 106 watts.

The amount of energy in 106 watts in one sec is 106 joules.

To calculate the energy of the 1kg falling water = Mgh

Energy = 1000*9.81*48

Energy = 470880 joules.

1 megawatt is = 1000000watts

The kilogram of water needed is 1000000/470880 = 2.124 kg of water

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Vector A has magnitude of 15.0 m/s and is 75° counter-clockwise up from the x-axis. What are the x- and y-components of the vect
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A block is attached to a horizontal spring and oscillates back and forth on a frictionless horizontal surface at a frequency of
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Answer:

Amplitude = 0.058m

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Explanation:

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½mv² = ½KA²

Make A the subject of formula

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Conversation of energy after split

½(m/2)V'² = ½(m/2)V² = ½KA'²

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Make A the subject of formula

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Substitute v\sqrt{\frac{m}{k} } for A in the above equation

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