Answer:
maximum possible temperature is 34.088°C
Explanation:
Given data
power output Q = 37 kW
volume flow rate = 11 x 10^-5 m3/s
temperature t = 14°C
to find out
maximum possible temperature T
solution
we can say
total water volume = 4 residents × volume flow
total water volume = 4 × 11 x 10^-5 = 44 × 10^-5 m³/s
so we say total water mass = 1000 × volume
total water mass = 1000 kg/m³ × 44 × 10^-5
total water mass = 0.44 kg
we know
dQ/dt = (dm/dt)× (S)× ( T - t)
so here we know specific heat of water S = 4.186 joule/gram °C
37 = 0.44 × 4.186 × (T-14)
T = 34.088°C
maximum possible temperature is 34.088°C
Answer:
a = 0.63 m/s²
Explanation:
given,
mass of submarine = 1460-kg
upward buoyant force = 16670 N
downward resistive force = 1150 N
submarine acceleration = ?
assuming g = 10 m/s²
now,
B - (R + mg) = ma
16670 - 1150 - 1460 × 10 = 1460 × a
1460× a = 920
a = 0.63 m/s²
hence, the acceleration of submarine is equal to a = 0.63 m/s²
Answer:
equilibrium position.
Explanation:
In simple harmonic motion , velocity v(t) is given by,
v(t) = -ω A sin(ωt + φ)
where
ω = angular velocity of the corresponding circular motion
A = amplitude
t = time
φ = the initial angle of the corresponding circular motion when the motion begin.
v (t) get maximized when sin value is maximized , i.e. sin 
=1
The particle has maximum speed when it passes through the equilibrium position.
Answer: car B has travelled 4times as far as Car A
d=vi*t+1/2at^2
No initial velocity so equation becomes;
d=1/2at^2 and the acceleration is the same between both only time is different;
Car A d=1/2a(1)^2
Car B d=1/2a(2)^2
Car A d= 1^2=1
Car B d= 2^2=4
Car B d=4*Car A
So car B has travelled 4 times as far as car A
Answer:
(a) 152.85 Nm
(b) 1528.5 Nm
Explanation:
According to the formula of power
P = τ ω
ω = 2 π f
(a) f = 2500 rpm = 2500 / 60 = 41.67 rps
So, 40 x 1000 = τ x 2 x 3.14 x 41.67
τ = 152.85 Nm
(b) f = 250 rpm = 250 / 60 = 4.167 rps
So, 40 x 1000 = τ x 2 x 3.14 x 4.167
τ = 1528.5 Nm
