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castortr0y [4]
3 years ago
6

A branching tree diagram begins with the

Chemistry
1 answer:
kherson [118]3 years ago
3 0
The idea behind a tree diagram is to start on the left with the whole thing, or one. Every time several possible outcomes exist the probability in that branch splits off into a smaller branch for each outcome.
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How do you calculate the density of a gas, based on its temperature and pressure?
stiks02 [169]
We can rearrange the ideal gas equation:
PV = nRT, where n is the number of moles equivalent to:
n = mass / Mr
PV = mRT/Mr
m/V = PMr/RT
density = PMr / RT; where Mr and R are constant.
5 0
3 years ago
Measure out 2.87 moles of sodium chloride (Nacl) into a clean dry cup. ​
Anettt [7]

Answer: weigh is m = n × M = 2.87 mol × 58.44 g/mol

Explanation: mass = amount of substance × molar mass

M((NaCl) = 22.99 +35.45

6 0
3 years ago
How many atoms are in 1.50 moles of fluorine gas
evablogger [386]
1.8x10^24 atoms is How many atoms are in 1.50 moles of fluorine gas
8 0
4 years ago
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Setler79 [48]

Answer:

8510 mol

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5 0
3 years ago
A flask with a volume of 125.0mL contains air with a density of 1.269 g/L. What is the mass of the air contained in the flask?
Aliun [14]
<span>In order to solve this problem you must first make sure all your numbers are in like terms. From the density value you can see that it is grams per liter. The first conversion you must do in convert the 125.0 mL value to Liters which you would do by dividing by 1000 because 1 liter is equal to 1000 mL. 125.0 divided by 1000 is 0.125 Liter. Now you will use the density equation to solve. The density equation is density is equal to mass divided by volume. Plug in your known numbers for density and volume. Then solve for mass. So Density (1.269 g/l is equal to mass divided by volume (.125 Liter) You must rearrange the equation to multiple density by volume which is 1.269 times 0.125 which will give you 0.1586. Because the Liters cancel each other out, the answer's unit will be grams. Your final answer is 0.1586 grams.</span>
4 0
3 years ago
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