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cluponka [151]
3 years ago
9

What is the mass of 2.50 moles of potassium chlorate in grams

Chemistry
1 answer:
Sedaia [141]3 years ago
3 0

Answer: 306 grams are there in 2.50 moles of potassium chlorate

Explanation

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

given mass of potassium chlorate = ?

Molar mass of potassium chlorate = 122.55 g/mol

Putting in the values we get:

2.50=\frac{xg}{122.55g/mol}

x=2.50mol\times 122.55g/mol=306g

306 grams are there in 2.50 moles of potassium chlorate

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Answer:

the reaction will shift towards the “heat”—shifts to the left

Explanation:

To summarize:

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o NOTE: The endothermic direction is always away from the “heat” term and the exothermic direction is

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3 years ago
Consider the reaction 2 al + Fe2O3 to 2Fe + Al2O3. If 60.0g of Al is reacted with excess Fe2O3, determine the amount (in moles)
olganol [36]

 The  amount  of  Al2O3  in moles=  1.11 moles    while in  grams   = 113.22 grams


    <em><u>calculation</u></em>

     2 Al  + Fe2O3 → 2Fe  + Al2O3

    step  1: find the moles of Al  by  use of <u><em>moles= mass/molar  mass  </em></u>formula

    =  60.0/27= 2.22  moles


    Step 2: use the mole ratio to determine the  moles of Al2O3.

 The  mole ratio  of Al : Al2O3 is  2: 1 therefore the moles of Al2O3= 2.22/2=1.11  moles


Step 3:    finds the mass  of  Al2O3  by us of  <u><em>mass= moles x molar mass</em></u><em> </em>formula.

The molar  mass of Al2O3  =  (2x27)  +( 16 x3) = 102  g/mol

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2 years ago
A 25.0 ml sample of 0.150 m hydrazoic acid is titrated with a 0.150 m naoh solution. what is the ph after 15.0 ml of the sodium
babunello [35]
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moles NH3 = molarity * volume 

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                   =  0.00375 moles

moles NaOH = molarity * volume 

                       = 0.15 m * 0.015 L

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after that we shoul get the total volume = 0.025L + 0.015L

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So we can get the concentration of NH3 & NaOH by:

∴[NH3] = moles NH3 / total volume 

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∴[NaOH] = moles NaOH / total volume 

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then, when we have the value of Ka of NH3 so we can get the Pka value from:

Pka = -㏒Ka 

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PH = 4.7 +㏒[0.05625/0.09375]

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<h3>Further explanation</h3>

Given

C₆H₁₂O₂ compound

Required

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Solution

In a compound, there is a mole ratio of the constituent elements.

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