If there is no net force on an object, then the object will <span>maintain it's rate of speed. Basically, net force is the change in an object's motion. If it is stationary and not moving, the object will stay stationary. If the object is moving at a rate of 2 miles per hour, it will constantly continue to move 2 mph because there is no net force.</span>
Neutron, proton
form those are both quarks
Here are your answers:
1. MgBr2 + Cl2 = MgCl2 + Br2
Balancing,
Already balanced.
Type of reaction: single displacement
2. Al + Fe2O3 = Al2O3 + Fe
Balancing,
2Al + Fe2O3 = Al2O3 + 2Fe
Type: single displacement reaction
3. AgNO3 + ZnCl2 = AgCl + N2O6Zn
Balancing,
2AgNO3 + ZnCl2 = 2AgCl + N2O6Zn
Type: double displacement reaction
MnO2
4. H2O2 ====== O2 + H20 [being catalyzed by manganese dioxide]
Balancing,
MnO2
2H2O2 ====== O2 + 2H2O
Type: decomposition reaction
5. Zn + HCl = ZnCl2 + H2
Balancing,
Zn + 2HCl = ZnCl2 + H2
Type: single displacement reaction
6. H2SO4 + NaOH = Na2SO4 + H2O
Balancing,
H2SO4 + 2NaOH = Na2SO4 + 2H2O
Type: Acid-base reaction
That took hella long!!! Hope it helps.
Answer:
ΔS° = -268.13 J/K
Explanation:
Let's consider the following balanced equation.
3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)
We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:
ΔS° = ∑np.Sp° - ∑nr.Sr°
where,
ni are the moles of reactants and products
Si are the standard molar entropies of reactants and products
ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]
ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]
ΔS° = -268.13 J/K
By changing the number of protons in an element, you are fundamentally changing it to a different element.
It’s worth remembering that:
Protons identify the element
Electrons determine properties and behavior of the element
Neutrons contribute to isotopes and just help keep everything stable, by separating the charges. Remember opposites attract. Like charges repel.
