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11Alexandr11 [23.1K]
3 years ago
14

For an RLC circuit in the limit of very high frequency, what is the effective behavior of the capacitor and the inductor in the

circuit?
Physics
1 answer:
Aliun [14]3 years ago
3 0

Answer:

Explanation:

Given

In R-L-C circuit frequency is very high

Inductive Reactance for inductor is given by X_L=2\pi f\cdot L

Inductive Reactance for Capacitor is given by X_c=\frac{1}{2\pi f\cdot C}

as frequency becomes too high then X_L will become very large and and X_cwill be approximately zero .

In other words inductor behave as a very high resistance and Capacitor behaves as very small resistance                            

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Compare the gravitational force on a 4 kg
Eddi Din [679]

Answer:

  • The gravitational force by the Earth on the object, and by the object on the Earth is

  • F = GMm/R²

  • = 6.674×10−11 m3⋅kg−1⋅s−2 × 6 × 10^24 kg × 44.5 kg/(6.4 × 10^6 m)²

  • = 435 N

<u>Please note that the ration between the gravitation force 435 and the mass 44.5</u>

  • should be gravitational acceleration

  • 435/44.5 = 9.78

  • I attribute the discrepancy between 9.78 and the usual 9.81 to rounding off in the

  • Earth's weight and radius.

The mass of the Moon is M / 81.3.

The radius of the Moon is R × 0.27.

The gravitational force on the moon would be

G(M/81.3)m/(R×0.27)² = 0.17×GMm/R²

The gravitational force on the moon is smaller by the factor of about 0.17.

6 0
2 years ago
A baseball (m=140g) traveling 32m/s moves a fielders
posledela

Answer:

Average force, F = 286.72 N

Explanation:

Given that,

Mass of the baseball, m = 140 g = 0.14 kg

Speed of the ball, v = 32 m/s

Distance, h = 25 cm = 0.25 m

We need to find the average  force exerted by the ball on the glove. It is solved using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh

F = mg

\dfrac{1}{2}mv^2=Fh

F=\dfrac{mv^2}{2h}

F=\dfrac{0.14\times (32)^2}{2\times 0.25}

F = 286.72 N

So, the average force exerted by the ball on the glove is 286.72 N. Hence, this is the required solution.

7 0
3 years ago
A group of hikers hear an echo 3.3 s after they shout. The temperature is 20◦C.
romanna [79]

Answer:

560 m

Explanation:

The speed of sound in air is approximately:

v ≈ v₀ + 0.6T

where v₀ is the speed of sound at 0°C (273 K) in m/s, and T is the temperature in Celsius.

The speed of sound at 20°C at that altitude is:

v ≈ 327 + 0.6(20)

v ≈ 339 m/s

The sound travels from the hikers to the mountain and back again, so it travels twice the distance.

339 m/s = 2d / 3.3 s

2d = 1118.7 m

d = 559.35 m

Rounding, the mountain is approximately 560 m away.

4 0
3 years ago
Can density be used to identify what a substance is made of?
Korolek [52]
Possibly, if you have list of densities and you have to match it. I can't think of any other scenarios in which it would be able to.

Hope I helped! :)
7 0
3 years ago
What is quantum physics? ​
lara [203]

Answer:

A fundamental theory that provides a description of the physical properties of nature at the scale of atoms and subatomic particles.

Explanation:

5 0
2 years ago
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