What is a rock that is full of tiny connected air spaces

Katena32 [7]

Answer:

Most of us have experienced that pivotal peak of pain, anger or frustration in which we want to scream “I hate my life.” Yet, the feeling that a dark cloud has specifically settled over us and our experiences can feel pretty isolating. The truth is, no matter how singled out or overwhelmed we feel, and no matter what area we are struggling in, we are not alone. More than half of U.S. workers are unhappy with their job. One in 10 Americans struggles with depression. All of us have moments of utter despair. Escaping from this hopeless-seeming state may feel impossible. Yet, in reality, we are not doomed, and we are not powerless. No matter what our circumstances, we can all learn tools to help us emerge from the darkest moments in our lives.

6 0

3 years ago

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A 1500 kg car is approaching the hill shown in the figure below at 10 m/s when it suddenly runs out of gas.

kenny6666 [7]

Based on the data, the car would reach a final velocity of 0 m/s. With a mass of 1500 kg, the momentum would be -15000 kg.m/sThank you for your question. Please don't hesitate to ask in Brainly your queries.

6 0

3 years ago

Walking along a 6-meter beam without falling helps to develop __________.

IrinaVladis [17]

C is correct answer.

Walking along a 6 meter beam without falling helps to develop balance.

Hope it helped.

-Charlie

4 0

3 years ago

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The frequency of a physical pendulum comprising a nonuniform rod of mass 1.15 kg pivoted at one end is observed to be 0.658 Hz.

S_A_V [24]

Answer:

The rotational inertia of the pendulum around its pivot point is $0.280\,kg\cdot m^{2}$ .

Explanation:

The angular frequency of a physical pendulum is measured by the following expression:

$\omega = \sqrt{\frac{m\cdot g \cdot d}{I_{o}} }$

Where:

$\omega$ - Angular frequency, measured in radians per second.

$m$ - Mass of the physical pendulum, measured in kilograms.

$g$ - Gravitational constant, measured in meters per square second.

$d$ - Straight line distance between the center of mass and the pivot point of the pendulum, measured in meters.

$I_{O}$ - Moment of inertia with respect to pivot point, measured in $kg\cdot m^{2}$ .

In addition, frequency and angular frequency are both related by the following formula:

$\omega =2\pi\cdot f$

Where:

$f$ - Frequency, measured in hertz.

If $f = 0.658\,hz$ , then angular frequency of the physical pendulum is:

$\omega = 2\pi \cdot (0.658\,hz)$

$\omega = 4.134\,\frac{rad}{s}$

From the formula for the physical pendulum's angular frequency, the moment of inertia is therefore cleared:

$\omega^{2} = \frac{m\cdot g \cdot d}{I_{o}}$

$I_{o} = \frac{m\cdot g \cdot d}{\omega^{2}}$

Given that $m = 1.15\,kg$ , $g = 9.807\,\frac{m}{s^{2}}$ , $d = 0.425\,m$ and $\omega = 4.134\,\frac{rad}{s}$ , the moment of inertia associated with the physical pendulum is:

$I_{o} = \frac{(1.15\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.425\,m)}{\left(4.134\,\frac{rad}{s} \right)^{2}}$

$I_{o} = 0.280\,kg\cdot m^{2}$

The rotational inertia of the pendulum around its pivot point is $0.280\,kg\cdot m^{2}$ .

8 0

3 years ago

Group of elements with the same number of valence electrons

bekas [8.4K]

Therefore, elements whose atoms can have the same number of valence electrons are grouped together in the periodic table of the elements. As a general rule, a main group element (except hydrogen or helium) tends to react to form a closed shell, corresponding to the electron configuration s2p6.

Hoped I Helped

4 0

3 years ago