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notsponge [240]
3 years ago
8

you uses 500 mg of sucrose and placed it into 200ml of water what is the concentration of this solution?

Chemistry
1 answer:
Assoli18 [71]3 years ago
3 0
We are given with 500 mg of sucrose dissoved in a 200 ml of water. The concentration of the solid is amount of solute per volume of the solvent. The concnetration can be expressed as 2.5 grams sugar per liter water or 250 mg per 100 ml water. 
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Carbon disulfide, a poisonous, flammable liquid, is an excellent solvent for phosphorus, sulfur, and some other nonmetals. A kin
ipn [44]

Answer:

Rate law: = k[CS_2]^1

Explanation:

Given:

t               [CS_2]

0.100            2.7 \times 10^{-7}

0.080          2.2 \times 10^{-7}

0.055         1.5\times 10^{-7}

0.044         1.2\times 10^{-7}

Rate law for the given reaction: k[CS_2]^n

Where, n is the order of the reaction.

Divide rate 1 with rate 3

\frac{0.100}{0.055} =\frac{k[CS_2 (1)]^n}{k[CS_2 (3)]^n} \\\frac{0.100}{0.055} =\frac{k[2.7 \times 10^{-7}]^n}{k[1.5\times 10^{-7}]^n}\\1.81=[1.8]^n\\ n=1

So, rate law = k[CS_2]^1

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