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3 years ago

Which component of the technological system is achieved when your camera takes a photograph?

Physics

2 answers:

IgorLugansk [536]3 years ago

8 0

When this component is achieved when your camera takes a photograph that is a GOAL.

Igoryamba3 years ago

4 0

Answer:

The Answer is goal

Explanation:

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I need answer fast please

Hatshy [7]

gold density = 38.6 *10^-3 / 2 *10^-6 = 19300 Kg/m3 Iron density = 46.8 *10^-3 / 6 *10^-6 = 7800 Kg/m3 water mass = density*volume = 1 * 10 = 10 grams = 0.01 Kg

4 0

3 years ago

Four electrons are located at the corners of a square 10.0 nm on a side, with an alpha particle at its midpoint.

dimulka [17.4K]

The work done by the Coulomb force will be " $6.08\times 10^{-21} \ J$ ".

Let us define the required work done to move that alpha particle to the one of the mid point of the side length as follows.

→ $W = \frac{4kqQ}{r_1} -(\frac{2kqQ}{r_2} +\frac{2kqQ}{r_3} )$

→ $=2kqQ(\frac{2}{r_1} -\frac{1}{r_2} -\frac{1}{r_3} )$

→ $=2(8.99\times 10^9)(-1.6\times 10^{-19})(2)(1.6\times 10^{-19})$

→ $= (\frac{2}{\sqrt{(5\times 10^{-9})^2+(5\times 10^{-9})} } -\frac{1}{(5\times 10^{-9})} -\frac{1}{\sqrt{(10\times 10^{-9})^2} +(5\times 10^{-9})^2} )$

→ $= 6.08\times 10^{-21} \ J$

Thus the above answer is appropriate.

Learn more about work done here:

brainly.com/question/24716770

3 0

2 years ago

A man 6.00 ft tall approaches a street light 15.0 ft above the ground at the rate of 4.00 ft/s. How fast is the end of the man

klio [65]

Answer:

$\frac{dx}{dt} = 10 ft/s$

Explanation:

As per given figure let say the tip of the shadow is at distance "x" from the base of the lamp

so here we have

$\frac{x}{15} = \frac{x - y}{6}$

so we have

$6x = 15 x - 15 y$

$15 y = 9 x$

now we have

$5\frac{dy}{dt} = 2\frac{dx}{dt}$

$5(4) = 2\frac{dx}{dt}$

$\frac{dx}{dt} = 10 ft/s$

7 0

3 years ago

Can someone give me 8-9

uysha [10]

8). A rubber band is storing more elastic energy in it when it's stretched.
It's the work you had to do to stretch it.

9). Radio, TV, microwave, infrared (heat), visible light, ultraviolet light, X-rays,
and gamma rays are all part of the electromagnetic spectrum, and all of them
carry energy from one place to another.

7 0

3 years ago

A resistor, inductor, and capacitor are connected in series, each with effective (rms) voltage of 65 V, 140 V, and 80 V respecti

Morgarella [4.7K]

Answer:

The value of the effective (rms) voltage of the applied source in the circuit is 132 V

Explanation:

Given;

effective (rms) voltage of the resistor, $V_R$ = 65 V

effective (rms) voltage of the inductor, $V_L$ = 140 V

effective (rms) voltage of the capacitor, $V_C$ = 80 V

Determine the value of the effective (rms) voltage of the applied source in the circuit;

$V= \sqrt{V_R^2 + (V_L^2-V_C^2} )\\\\V= \sqrt{65^2 + (140^2-80^2} )\\\\V = \sqrt{4225+ 13200} \\\\V = \sqrt{17425} \\\\V = 132 \ V$

Therefore, the value of the effective (rms) voltage of the applied source in the circuit is 132 V.

6 0

4 years ago