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Dmitry_Shevchenko [17]
4 years ago
10

The development of nuclear power has provided electricity for less money, but at a cost. What may be considered a "cost" of nucl

ear power?
Physics
1 answer:
Jlenok [28]4 years ago
8 0
Nuclear power generates alot of power, ALOT. It requires Uranium and other radioactive substances to power it, which over time can degrade and become depleted. This radioactive waste would have to be placed somewhere, and it accumulates over time slowly. 
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A 27.0-g object moving to the right at 21.5 cm/s overtakes and collides elastically with a 11.0-g object moving in the same dire
7nadin3 [17]

Answer:

final speed of the first object: 17.73 cm/s

final speed of the second object: 24.23 cm/s

Explanation:

Data:

mass of the first object, m1 = 27.0 g

mass of the second object, m2 = 11.0 g

initial speed of the first object, v1i = 21.5 cm/s

initial speed of the second object, v2i = 15 cm/s

final speed of the first object, v1f = ? cm/s

final speed of the second object, v2f = ? cm/s

Elastic collisions formula:

v1f = (m1 - m2)/(m1 + m2) * v1i + 2*m2/(m1 + m2) * v2i

v1f = (27 - 11)/(27 + 11) * 21.5 + 2*11/(27 + 11) * 15

v1f = 17.73 cm/s

v2f = 2*m1/(m1 + m2) * v1i + (m2 - m1)/(m1 + m2)*v2i

v2f = 2*27/(27 + 11) * 21.5 + (11 - 27)/(27 + 11)*15

v2f = 24.23 cm/s

8 0
3 years ago
A supply plane needs to drop a package of food to scientists working on a glacier in Greenland. The plane flies 110 m above the
zysi [14]

Answer:

The distance is 709.5 m.

Explanation:

Given that,

Speed = 150 m/s

Distance = 110 m

Suppose, How far short of the target should it drop the package?

We need to calculate the time

Using equation of motion

s=ut+\dfrac{1}{2}gt^2

t^2=\dfrac{2s}{g}

Where, g = acceleration due to gravity

t = time

Put the value into the formula

t=\sqrt{\dfrac{2\times110}{9.8}}

t=4.73\ sec

We need to calculate the distance

Using formula of distance

d= vt

Put the value into the formula

d=150\times4.73

d=709.5\ m

Hence, The distance is 709.5 m.

8 0
3 years ago
When the point of reference (the observer) is in motion, it flips the "rules" of vector addition (you ADD the vectors going in o
KengaRu [80]

Answer:

the statement is TRUE

Explanation:

When we move in the same direction, the relative speed of the two vehicles is lower, so we must subtract their speeds, if the result is positive the vehicles approach and if it is negative they move away.

      v_relative = v₁ - v₂

When the two vehicles go in opposite directions, the speed is much higher, so we must add their speeds

     v_relative = v₁ - (-v₂))

     v_relative = v₁ + v₂

therefore the statement is TRUE

3 0
3 years ago
The major evidence for the idea that the expansion of the universe is accelerating comes from observations of:
elena-14-01-66 [18.8K]
The redshirting of the spectra of distant galaxies.  They are moving away from us at a rate proportional to their distance
7 0
4 years ago
A load of 500N is carried by 200N effort in a simple machine having load distance 3m Calculate effort distance.​
vlada-n [284]

Answer:

<h2>2.5 m</h2>

Explanation:

Load ( L ) = 500 N

Effort ( E ) = 200 N

Load distance ( LD ) = 3 m

Effort distance ( ED ) = ?

Now, Let's find the Effort distance ( ED )

We know that,

Output work = Input work

i.e L × LD = E × ED

plug the values

500 \times 3 = 200 \times ED

multiply the numbers

1500 = 200 \times ED

Swipe the sides of the equation

200 \: ED \:  = 500

Divide both sides of the equation by 200

\frac{200 \: ED}{200}  =  \frac{500}{200}

Calculate

ED\:  = 2.5 \: m

Hope this helps..

best regards!!

5 0
3 years ago
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