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Akimi4 [234]
3 years ago
7

What is a redox reaction?

Chemistry
2 answers:
Novay_Z [31]3 years ago
7 0
An oxidation-reduction (redox<span>) </span>reaction<span> is a type of chemical </span>reaction<span> that involves a transfer of electrons between two species. An </span>oxidation<span>-reduction </span>reaction<span> is any chemical </span>reaction<span> in which the </span>oxidation<span> number of a molecule, atom, or ion changes by gaining or losing an electron</span>
Yuri [45]3 years ago
5 0
In simple and easy way ,

Redox reaction is the sum of both oxidation and reduction !

Where ever both are taking place , you should call that redox reaction !
You might be interested in
Calculate the number of moles of Cl2 produced at equilibrium when 3.98 mol of PCl5 is heated at 283.9 deg celsius in a vessel ha
ddd [48]

Answer:

1.274 moles

Explanation:

The equation for the reaction can be represented as follows:

                       PCl_5(g)           ⇄       PCl_3(g)     +         Cl_2(g)

K = 0.060

K = \frac{[PCl_3][Cl_2]}{[PCl_5]}

Concentration of   PCl_5(g)  = \frac{numbers of moles}{volume}

Concentration of   PCl_5(g)  = \frac{3.98}{10.0}

Concentration of   PCl_5(g)  = 0.398 moles

If we construct an ICE table for the above equation; we have:

                       PCl_5(g)           ⇄       PCl_3(g)     +         Cl_2(g)

Initial                0.398                          0                          0

Change            - x                               + x                        + x

Equilibrium    (0.398 - x)                      x                          x

K = \frac{[PCl_3][Cl_2]}{[PCl_5]}

K = \frac{[x][x]}{[0.398-x]}

K = \frac{x^2}{0.398-x}

0.060 = \frac{x^2}{0.398-x}

0.06(0.398-x) = x²

0.02388 - 0.060x = x²

x² + 0.060x - 0.02388 = 0               (quadratic equation)

a = 1;       b= 0.06;      c= -0.02388

Using quadratic formula;

=  \frac{-b+/-\sqrt{b^2-4ac} }{2a}

= \frac{-0.06+/-\sqrt{(0.06)^2-4(1)(-0.02388)} }{(2*1)}

= \frac{-0.060+/-\sqrt{0.0036+0.09552} }{2}

= \frac{-0.06+/-\sqrt{0.09912} }{2}

= \frac{-0.06+/-0.3148}{2}

= \frac{-0.060+0.3148}{2}   or \frac{-0.060-0.3148}{2}

= \frac{0.2548}{2}  or \frac{-0.3748}{2}

= 0.1274 or -0.1874

We go by the positive value which says:

[x] = 0.1274 M

number of moles = 0.1274 × 10.0

= 1.274 moles

∴ the number of moles  of Cl₂ produced at equilibrium = 1.274 moles

7 0
3 years ago
The reaction described in part a required 3.35 l of calcium chloride. what is the concentration of this calcium chloride solutio
kupik [55]
Assuming you are talking about the atomic mass of calcium chloride...
M = n/V
M = 1/3.35
M = 0.298
5 0
3 years ago
What factors could have affected your results?
AleksandrR [38]

Answer:

See below  

Step-by-step explanation:

heat gained by metal + heat lost by water = 0

           m₁C₁ΔT₁           +         m₂C₂ΔT₂         = 0

C₁ = -(m₂C₂ΔT₂)/(m₁ΔT₁)

The factors determining C₁ are

  • mass of water
  • temperature change of water (T_f - Ti)
  • mass of metal
  • temperature change of metal (T_f - Ti)

Any factor that makes the numerator higher or the denominator lower than what you thought, will give a calculated C₁ that is too high (and vice versa).

The major sources of uncertainty are probably in determining the temperatures, especially the initial and final temperatures of the metal. However, you will have to decide what the principal factors were in your experiment.

For example, did the metal have a chance to cool during the transfer to the calorimeter? How easy was it to determine the equilibrium temperature, etc?

Factors Affecting the Calculation of Specific Heat Capacity

<u>          Too Low                 </u>              <u>      Too high                   </u>              

Water                                             Water

    Mass less than thought                Mass more than thought

    Ti lower                                         Ti higher

    T_f higher                                       T_f lower

Metal                                              Metal

    Mass more than thought             Mass less than thought

    Ti higher                                       Ti lower

8 0
3 years ago
Suppose you mix one mole of sulfuric acid (H2SO4) with 1 mole of sodium hydroxide(NaOH).
olasank [31]

Answer & Explanation:

  • The neutralization of H₂SO₄ with NaOH is occurred according to the balanced equation:

<em>H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O,</em>

It is clear that every 1.0 mol of H₂SO₄ needs 2 mol of NaOH to be neutralized completely.

<em>So, when you mix one mole of sulfuric acid with 1 mole of sodium hydroxide, there will be an excess of sulfuric acid.</em>

<em>Thus, the pH of the solution remain below 7.</em>

7 0
3 years ago
8. Write a balanced chemical equation showing how you could prepare each of the following salts from an
polet [3.4K]

Answer:

according to my reading

use own words

Explanation:

Salts are combinations of acids and bases. The cation comes from a base and the anion from an acid. Therefore, to make KNO3 we react KOH and HNO3. See how that is done? We write K and add OH to make KOH. We take NO3 and add H to make HNO3.

6 0
3 years ago
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