Molar mass FeSO₄ =151.908 g/mol
Volume = 450 mL / 1000 = 0.45 L
1 mol ----------- 151.908 g
n mol ----------- 0.8 g
n = 0.8 * 1 / 151.908
n = 0.00526 moles
M = n / V
M = 0.00526 / 0.45
M = 0.01168 mol/L⁻¹
hope this helps!
The strategy here would be to convert mass to moles and then from moles to the number of atoms.
100.0 g of iron(iii) oxide, or Fe2O3, has a molar mass of 159.687 g/mol. To convert the mass into the number of moles, divide the mass by the molar mass: (100.0 g)(159.687) = 0.6262 moles Fe2O3.
1 mole of any substance is, by definition, equal to 6.022 • 10^23 units of that substance. So to compute the number atoms contained in 0.6262 moles of Fe2O3, multiply (0.6262)(6.022 • 10^23) = 3.771 • 10^23 atoms of iron(iii) oxide, which is your answer (given to four significant figures).
Explanation:
first one, a. lithium. it's the largest
Answer:
IONIC BOND
Explanation:
the force between oppositely charged IONS is and IONIC BOND