Question

A thin sheet of iridium metal that is 3.12 cm by 5.21 cm has a mass of 87.2 g and a thickness of 2.360 mm. What is the density of iridium?

Answer 1

Answer:

Therefore the density of the sheet of iridium is 22.73 g/cm³.

Explanation:

Given, the dimension of the sheet is 3.12 cm by 5.21 cm.

Mass: The mass of an object can't change with respect to position.

The S.I unit of mass is Kg.

Weight of an object is product of mass of the object and the gravity of that place.

Density: The density of an object is the ratio of mass of the object and volume of the object.

$Density =\frac{mass}{volume}$

            $=\frac{Kg}{m^3}$                 [S.I unit of mass= Kg and S.I unit of m³]

Therefore the S.I unit of density = Kg/m³

Therefore the C.G.S unit of density=g/cm³

The area of the sheet is = length × breadth

                                        =(3.12×5.21) cm²

                                       =16.2552 cm²

Again given that the thickness of the sheet  is 2.360 mm =0.2360 cm

Therefore the volume of the sheet is =(16.2552 cm²×0.2360 cm)

                                                             =3.8362272 cm³

Given that the mass of the sheet of iridium is 87.2 g.

$Density =\frac{87.2 g}{3.8362272 cm^3}$

             =22.73 g/cm³

Therefore the density of the sheet of iridium is 22.73 g/cm³.