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r-ruslan [8.4K]

3 years ago

7

An insoluble solid material that is produced in double replacement reactions is called

1 answer:

lina2011 [118]3 years ago

4 0

Answer:

Precipitate

Explanation:

When a double displacement reaction occurs, the cations and anions switch partners, resulting in the formation of two new ionic compounds AD and CB, one of products is in the solid state and forms an insoluble ionic compound called a precipitate.

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Two boxes are connected to each other by a string as shown in the figure. The 10-n box slides without friction on the horizontal

FromTheMoon [43]

Answer:

T=7.4 N hence T<30 N

Explanation:

The figure is likely to be similar to the one attached. Writing the equation for forces we have

F-T=Fa/g where F is the force, T is tension, a is acceleration and g is acceleration due to gravity. Substituting the figures we have the first equation as

30 N - T = (30/9.81)a

Also, we know that T=F*a/g and substituting 10N for F we obtain the second equation as

T = (10/9.81)a

Adding the first and second equations we obtain

30 = 4.077471967

a Hence

$a=\frac {30}{4.077471967}=7.3575 m/s^{2}$

and T=a hence

T is approximately 7.4 N

5 0

3 years ago

Read 2 more answers

A 100 kg bag of sand has a weight on 100 N. When dropped its acceleration is what?

Anettt [7]

Answer:

The acceleration of the bag of sand is $1\ m/s^2$ .

Explanation:

We have,

Mass of a bag of sand is 100 kg

Weight of the bag of sand is 100 N

It is required to find the acceleration of the bag when it is dropped. The weight of an object is given by :

$F =ma$

When it is dropped, a = g

$g=\dfrac{F}{m}\\\\g=\dfrac{100}{100}\\\\g=1\ m/s^2$

So, the acceleration of the bag of sand is $1\ m/s^2$ .

4 0

4 years ago

A wire runs left to right and carries a current in the direction shown.

Step2247 [10]

Answer:

The direction of the magnetic field at point Z; Into the screen

Explanation:

8 0

4 years ago

Read 2 more answers

In April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min, 43.6 s. Suppose "Pre" was at the 8.13 km mark at a

SOVA2 [1]

Answer: $0.084 m/s^2$

Explanation:

Given

Total time=27 min 43.6 s=1663.6 s

total distance=10 km

Initial distance $d_1=8.13 km$

time taken=25 min =1500 s

initial speed $v_1=\frac{8.13\times 1000}{25\times 60}=5.6 m/s$

after 8.13 km mark steve started to accelerate

speed after 60 s

$v_2=v_1+at$

$v_2=5.6+a\times 60$

distance traveled in 60 sec

$d_2=v_1\times 60+\frac{a60^2}{2}$

$d_2=336+1800 a$

time taken in last part of journey

$t_3=1663.6-1560=103.6 s$

distance traveled in this time

$d_3=v_2\times t_3$

$d_3=\left ( 5.6+a\times 60\right )103.6$

and total distance $=d_1+d_2+d_3$

$10000=8.13\times 1000+336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$1870=336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$a=0.084 m/s^2$

5 0

4 years ago

a hockey puck with a mass of 0.11 kg is at rest on the horizontal frictionless surface of the rink. a player applies a horizonta

stira [4]

The solution to this ques is available in the image.

Given,

Force= 1N

Mass= 0.11kg

Time= 5sec

Force= mass X accelaration

Accelaration= velocity/ time

Speed=distance/ time

Hence, the speed is 45 m/s and the distance is 225 m.

To know more about speed and distance problems the link is given below:

brainly.com/question/19610984?

#SPJ4

8 0

2 years ago