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snow_tiger [21]
3 years ago
13

What Number Am I?

Engineering
1 answer:
noname [10]3 years ago
5 0

Answer:

The number is 768

Explanation:

The given parameters of the three digits number are;

The number is a multiple of four, therefore, a factor of the number = 4

The value of the first digit = A prime number larger than 5

The sum of the last two digits > 10

The value of the ones (place value) digit > The tens (place value) digit

Let 'xyz' represent the digits of the three digits number, we have;

x = A prime number digit larger than 5

∴ x = 7

y + z > 10

z > y and z > x

Given that 4 is a factor of the number, we have;

4 is a factor of 'z'

4 is also a factor of yz

Therefore, the digit, z > 7 and z is divisible by 4, therefore, z = 8

y + z = y + 8 > 10

∴ y > 10 - 8

y > 2

The multiples of 4 larger than 728 with the last digit equal to 8 are found using Microsoft Excel and presented as follows;

748, 768, 788

The numbers that have a larger ones place value are; 748 and 768

The sum of the las two digits are therefore, 4 + 8 = 12 and 6 + 8 = 14

The number that has the largest ones place value for the sum of the last two digits is 768

The number is 768

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Complete Question

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