Given:
175 kilograms of Methane (CH4) to be synthesized into Hydrogen Cyanide (HCN)
The balanced chemical equation is shown below:
2 CH4<span> + 2 NH</span>3<span> + 3 O</span>2<span> → 2 HCN + 6 H</span>2<span>O
</span>
To calculate for the masses of ammonia and oxygen needed, our basis will be 175 kg CH4.
Molar mass:
CH4 = 16 kg/kmol
NH3 = 17 kg/kmol
O2 = 32 kg/kmol
mass of NH3 = 175 kg CH4 / 16 kg/kmol * (2/2) * 17 kg/kmol
mass of NH3 = 185.94 kg NH3 needed
mass of O2 = 175 kg CH4 / 16 kg/kmol * (3/2) * 32 kg/kmol
mass of O2 = 525 kg
mass of O = 525 kg / 32 kg/kmol * (1/2) * 16 kg/kmol
mass of O = 131.25 kg O
Their atomic number increases
Answer:
215 amu
Explanation:
In the reactants:
There is 1 iron atom, 3 chlorine atoms, 6 hydrogen atoms and 3 oxygen atoms:
- Fe: 56 × 1 = 56
- Cl: 35 × 3 = 105
- H: 1 × 6 = 6
- O: 16 × 3 = 48
56 + 105 + 6 + 48 = 215 amu
Hope this helps!
D is the answer I believe.
