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Studentka2010 [4]
3 years ago
14

If the amplitude of the resultant wave is twice as great as the amplitude of either component wave, and the wave exhibits reinfo

rcement, the component waves must
A. Have a different wave length than the resultant wave
B. Be in phase with each other
C. Have a different frequency than the resultant wave
D. Be traveling in the opposite direction of the resultant wave
Physics
2 answers:
shutvik [7]3 years ago
8 0

Correct answer choice is:

B. Be in phase with each other.

____________________________________________________________

Explanation:

Components waves mix to produce a resultant with the equivalent wavelength but the amplitude which is bigger than the amplitude of both of the unique component waves, and this results in constructive interference, which states that the interference of two or more waves of identical frequency and phase, constructing in their respective reinforcement and constructing a single amplitude equivalent to the total of the amplitudes of the unique waves.

Lunna [17]3 years ago
5 0
Be in phase with each other! otherWise B
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A straight segment of wire 35.0 cm long carrying a current of 2.60 A is in a uniform magnetic field. The segment makes an angle
den301095 [7]

Answer:

Magnetic field, B = 0.275 T

Explanation:

Given that,

Length of the wire, L = 35 cm = 0.35 m

Current carried in the wire, I = 2.6 A

The segment makes an angle of 53∘ with the direction of the magnetic field, \theta=53^{\circ}

Magnetic force, F = 0.2 N

To find,

The magnitude of the magnetic field.

Solution,

The magnetic force acting on the wire is given by :

F=ILBsin\theta

\theta is the angle between the length of wire and the magnetic field.

0.2=2.6\times 0.35\times B\times sin(53)

B = 0.275 T

Therefore, the magnitude of the magnetic field is 0.275 T. Hence, this is the required solution.

5 0
3 years ago
A jet airliner moving initially at 504 mph (with respect to the ground) to the east moves into a region where the wind is blowin
adelina 88 [10]

Answer

given,

intial velocity = 504 mph

wind speed = 219 mph

at an angle of 29◦

from the data

 The resultant velocity =

V = V_x \hat{i} + V_y\hat{j}

 V = (504 + 219 cos 29^0 ) \hat{i} +(219 sin 29^0 )\hat{j}

 V = 695.54\hat{i} + 106.17 \hat{j}

the magnitude of velocity

V = \sqrt{695.54^2+106.17^2}

V = 703.59 m/s

direction

tan θ =  \dfrac{106.17}{695.54}

θ = 8.676°

8 0
4 years ago
How can a wind turbine be used to make an electric circuit?
Radda [10]

Answer:

Wind turbines operate on a simple principle. The energy in the wind turns two or three propeller-like blades around a rotor. The rotor is connected to the main shaft, which spins a generator to create electricity.

Explanation:

7 0
3 years ago
Which statement correctly describes the current in a circuit that is made up of any two resistors connected in series with a bat
jeyben [28]
The correct answer is
<span>C. The current in the battery and in each resistor is the same.

In fact, when resistors are connected in series, the current flowing through them is the same in each resistor. This is also equal to the current flowing in the circuit, so it is the same as the current flowing through the battery.</span>
6 0
3 years ago
Suppose that a comet has a very eccentric orbit that brings it quite close to the Sun at closest approach (perihelion) and beyon
Nutka1998 [239]

Answer:

16.63min

Explanation:

The question is about the period of the comet in its orbit.

To find the period you can use one of the Kepler's law:

T^2=\frac{4\pi}{GM}r^3

T: period

G: Cavendish constant = 6.67*10^-11 Nm^2 kg^2

r: average distance = 1UA = 1.5*10^11m

M: mass of the sun = 1.99*10^30 kg

By replacing you obtain:

T=\sqrt{\frac{4\pi}{GM}r^3}=\sqrt{\frac{4\pi^2}{(6.67*10^{-11}Nm^2/kg^2)(1.99*10^{30}kg)}(1.496*10^8m)^3}\\\\T=997.9s\approx16.63min

the comet takes around 16.63min

8 0
3 years ago
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