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Nookie1986 [14]
3 years ago
12

A skier rides a ski-lift up to the top of the mountain, 1600 m above sea level. If the skier has a mass of 74 kg, how much poten

tial energy does the skier have at the top of the hill (assuming PE = 0 J is at sea level)?
Physics
1 answer:
statuscvo [17]3 years ago
3 0

Answer:

I think it is 1.16 MJ

Explanation:

PE=mgh

PE=(74)(9.81)(1600)= 1,161,504J = 1.16MJ

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If a block of wood has a density of 0.6g/cm3 and a mass of 120g what is the volume
Luda [366]

Answer:

It would be 39 :))

Explanation:

6 0
3 years ago
un resorte de 10cm de longitud recibe una magnitud de fuerza que lo estira hasta medir 15cm ¿cual es la magnitud de la tension u
Ber [7]

Answer: 0.5

Explanation:

The modulus of elasticity (called <em>"alargamiento unitario"</em> in spanish) \epsilon of a spring is given by the following formula:

\epsilon=\frac{\Delta L}{L}

Where:

L=10 cm  is the original length of the spring

\Delta L=L_{f}-L  is the elongation of the spring, being L_{f}=15 cm the length of the spring after a force is applied to it.

\epsilon=\frac{L_{f}-L}{L}=\frac{15 cm - 10 cm}{10 cm}

Then:

\epsilon=0.5

8 0
3 years ago
If the electrical field in some region or space is zero, does that imply that there is no electrical charge in that region?
mrs_skeptik [129]
No
It means the resultant electrical charges had canceled each other out so there is no field to be sensed .
7 0
3 years ago
The equation P^xV^yT^z= constant is Boyle law for what is the values of x,y,z​
Setler79 [48]

Answer:

x = 1, y = 1 and z = 0

Explanation:

Given equation;

P^x V^y T^z = constant

Boyle's law states that at constant temperature, the volume of a fixed mass of gas is inversely proportional to its pressure.

Mathematically the law is written as;

PV = constant

From the given equation, the values of x, y and z that will match this law is calculated as follows;

P^1 V^1 T^0 = constant\\\\P^1 = P\\\\V^1 = V\\\\T^0 = 1\\\\P \times V \times 1 = PV = constant\\\\Thus, x = 1, \ y = 1 \ \ and \ z = 0

6 0
3 years ago
In odd nuclei, what determines the final spin of the nucleus?
Katen [24]

Answer:

In odd nuclei, the left out proton or neutron will contribute to the spin of the nucleus.

Explanation:

The meaning of odd nuclei is atomic mass is odd.

A=odd number.

A=Z+n

Here, Z is proton either it will odd or n will odd which is neutron.

Now according to the shell model the left out proton or neutron will contribute to the spin and parity.

For example,

Take the case of isotope of nitrogen-15.

Here Z is 7, and n is 8 will not contribute in spin.

Now, for Z=7.

1S^{2} _{\frac{1}{2} }, 1P^{4} _{\frac{3}{2} }, 1P^{1} _{\frac{1}{2} }

Here,

j=\frac{1}{2}

and, L=1.

Fort parity,

(-1)^{L}

Put the value of L.

Parity will be -1.

Now, spin will be

S=(\frac{1}{2} )^{-1}.

7 0
3 years ago
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