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aleksandrvk [35]
3 years ago
7

An automobile is driven on a straight road, and the distance traveled by the automobile after time t=0 is given by a quadratic f

unction a where a(t) is measured in feet and t is measured in seconds for 0 <= t <= 12. Of the following, which gives the best estimate of the velocity of the automobile, in feet per second, at time t = 8 seconds?
a. s(8)
b. s(8)/8
c. s(12)- s(2)/ 12-2
d. s(9)- s(7)/9-7
Physics
1 answer:
TEA [102]3 years ago
8 0

Answer:

Velocity = \frac{s(8)}{8}

Explanation:

Given

0 \leq t \leq 12

Required

Determine the velocity when t = 8

This type of velocity is referred to as an instantaneous velocity.

In this case, it is calculated using

Velocity = \frac{Distance\ at\ 8 second}{t = 8}

Given that s(t) models the distance;

s(8) = distance at 8 seconds

So;

Velocity = \frac{s(8)}{8}

Option B answers the question

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Norma-Jean [14]

Answer:

The batteries would be connected in series while the bulbs would be connected in parallel

Explanation:

Power (W) = VI

where V = voltage, I = current and R = resistance

from V = IR , I = V/R

Power (W) now becomes = V (V/R) = \frac{V^{2} }{R}

Power (W) =  \frac{V^{2} }{R}

from the above equation, power is directly dependent on voltage, hence the voltage has to be high for the power to be high and the power is also inversely dependent on the resistance (in this case the bulbs which act as the load)

  • We have to batteries, when batteries are connected in series the total voltage becomes the summation of the two voltages hence giving a higher voltage and when they are connected in parallel their voltage remains the same. Since we want to get higher voltage we will connect the two batteries in series.
  • we have two bulbs which are the resistance here, from the equation above the power is inversely dependent on the resistance so we would need its value to be minimal. When resistance is connected in series the resistance individual will be added to get the total resistance, hence the total resistance will be high but when the resistors are arranged in parallel you get the total resistance by applying the formula \frac{R1R2}{R1+R2} which will give us a lower resistance. Hence we would connect the bulbs in parallel.

Take note that the power from this connection should not exceed the bulbs power rating so as to avoid damage of the bulbs.

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The famous leaning tower of pisa doesn't topple over because its center of gravity is
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Vertical line from the centre of mass is inside the base of the tower.
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If rho(x,y) is the density of a wire (mass per unit length), then
lidiya [134]

Answer:

See description

Explanation:

With the given information we have:

x(t) = 1 + cos(t)\\ y(t)=sin(t)\\ \rho(x,y) = 3x

the interval is [0,\pi ]

now the mass m has the given expression:

m = \int \rho(x,y) dS

we will use the formula for a line integral and let:

dS=\sqrt{x'(t)^2 + y'(t)^2}=\sqrt{cos(t)^2 + sin(t)^2}dt=dt

therefore we have:

m=\int \rho(x,y)dS=\int\limits^\pi_0 {3*x}dS=\int\limits^\pi _0{3*(1+cos(t))dS\\=\int\limits^\pi _0{3*(1+cos(t))dt

we solve the integral:

m=3*\int\limits^\pi _0{(1+cos(t))dt= 3*(t+sin(t))\limits^\pi _0=3*\pi=9.42

7 0
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A 16000 kg railroad car travels along on a level frictionless track with a constant speed of 23.0 m/s. A 5400 kg additional load
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Answer:

The speed of the car when load is dropped in it is 17.19 m/s.

Explanation:

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Mass of the railroad car, m₁ = 16000 kg

Speed of the railroad car, v₁ = 23 m/s

Mass of additional load, m₂ = 5400 kg

The additional load is dropped onto the car. Let v will be its speed. On applying the conservation of momentum as :

m_1v_1=(m_1+m_2)v

v=\dfrac{m_1v_1}{m_1+m_2}

v=\dfrac{16000\ kg\times 23\ m/s}{(16000+5400)\ kg}

v = 17.19 m/s

So, the speed of the car when load is dropped in it is 17.19 m/s. Hence, this is the required solution.

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